Reputation: 169
I've been set the 'challenge' of converting seconds to format as the Days,Minutes and Seconds.
For example: 31600000 = 365 days, 46 minutes, 40 seconds.
using namespace std;
const int hours_in_day = 24;
const int mins_in_hour = 60;
const int secs_to_min = 60;
long input_seconds;
cin >> input_seconds;
long seconds = input_seconds % secs_to_min;
long minutes = input_seconds / secs_to_min % mins_in_hour;
long days = input_seconds / secs_to_min / mins_in_hour / hours_in_day;
cout << input_seconds << " seconds = "
<< days << " days, "
<< minutes << " minutes, "
<< seconds << " seconds ";
return 0;
It works and comes up with the correct answer but after completing it I looked at how other people had tackled it and theirs was different. I'm wondering If I'm missing something.
Upvotes: 13
Views: 34613
Reputation: 1
Convert seconds to days, hours, minutes, and seconds; it works perfectly without consuming many resources:
#include <iostream>
using namespace std;
int main()
{
const int Seconds_Per_Day = 86400;
const short Seconds_Per_Hour = 3600;
const short Seconds_Per_Minute = 60;
int Input_Seconds;
cout << "Please, enter seconds: \n";
cin >> Input_Seconds;
short Number_Of_Days = floor(Input_Seconds / Seconds_Per_Day);
int Reminder_1 = Input_Seconds % Seconds_Per_Day;
short Number_Of_Hours = floor(Reminder_1 / Seconds_Per_Hour);
short Reminder_2 = Reminder_1 % Seconds_Per_Hour;
short Number_Of_Minutes = floor(Reminder_2 / Seconds_Per_Minutes);
short Number_Of_Seconds = Reminder_2 % Seconds_Per_Minutes;
cout << "The number of days is " << Number_Of_Days << ", of hours is " <<
Number_Of_Hours << ", of minutes is " << Number_Of_Minutes << ", and of
seconds is " << Number_Of_Seconds << endl;
return 0;
}
Upvotes: -1
Reputation: 223
this seems to me to be the easiest way to convert seconds into DD/hh/mm/ss:
#include <time.h>
#include <iostream>
using namespace std;
time_t seconds(1641); // you have to convert your input_seconds into time_t
tm *p = gmtime(&seconds); // convert to broken down time
cout << "days = " << p->tm_yday << endl;
cout << "hours = " << p->tm_hour << endl;
cout << "minutes = " << p->tm_min << endl;
cout << "seconds = " << p->tm_sec << endl;
Upvotes: 11
Reputation: 71
I think is the challenge from Stephen Prata's book. I did it as follows:
#include <iostream>
using namespace std;
int main()
{
long input_seconds = 31600000;
const int cseconds_in_day = 86400;
const int cseconds_in_hour = 3600;
const int cseconds_in_minute = 60;
const int cseconds = 1;
long long days = input_seconds / cseconds_in_day;
long hours = (input_seconds % cseconds_in_day) / cseconds_in_hour;
long minutes = ((input_seconds % cseconds_in_day) % cseconds_in_hour) / cseconds_in_minute;
long seconds = (((input_seconds % cseconds_in_day) % cseconds_in_hour) % cseconds_in_minute) / cseconds;
cout << input_seconds << " seconds is " << days << " days, " << hours << " hours, " << minutes << " minutes, and " << seconds << " seconds.";
cin.get();
return 0;
}
Upvotes: 7
Reputation: 47105
For example: 31600000 = 365 days, 46 minutes, 40 seconds.
Really?
$ bc
365*24*60*60 + 46*60 + 40
31538800
365*24*60*60 + 1066*60 + 40
31600000
Did you mean "convert the input into days, hours, minutes and seconds, and then discard the hours" or "convert the input into days, total minutes within a day (i.e. can be more than 60), and seconds"?
In the second case I think you should replace the instruction for minutes with
long minutes = input_seconds / secs_to_min % (mins_in_hour * hours_in_day);
Upvotes: 1
Reputation: 101506
One of the things about programming is that there is never just one way to do something. In fact if I were to set my mind to it, I might be able to come up with a dozen completely different ways to accomplish this. You're not missing anything if your code meets requirements.
For your amusement, here's a way to format up hours:minutes:seconds under Windows (elapsed
is a double & represents number of seconds elapsed since... something)
sprintf_s<bufSize>(buf, "%01.0f:%02.0f:%02.2f", floor(elapsed/3600.0), floor(fmod(elapsed,3600.0)/60.0), fmod(elapsed,60.0));
Upvotes: 6