Reputation: 3972
Can you create a list of functions and then execute them sequentially, perhaps passing them into do notation?
I'm currently doing this by mapping over a list of data and am wondering if I can call somehow pass the result as a series of sequential calls?
Upvotes: 5
Views: 542
Reputation: 4249
good answers so far, but if you also want each function to act not on the original data but on the result of the previous function, look at the foldding functions, such as foldl, foldl1, and foldr:
fns = [(1-), (+2), (abs), (+1)]
helperFunction a f = f a
test1 n = foldl helperFunction n fns
and you may need the monadic version, foldM and foldM_ :
import Control.Monad
import Data.Char
helperFunction a f = f a
prnt = \s-> do putStrLn s; return s
actions = [return, prnt, return.reverse, prnt, return.(map toUpper), prnt, return.reverse, prnt]
test2 str = foldM_ helperFunction str actions
Upvotes: 3
Reputation: 18389
If these are functions, ie pure, then you can use ($)
or "apply":
execute functions argument = map ($argument) functions
-- execute [id,(1+),(1-)] 12 => [12,13,-11]
There's no guarantee that this happens sequentially of course, but you'll get a list of the return values.
If these are actions, ie impure, then what you want is called sequence_
:
sequence_ [putStr "Hello", putStr " world", putStrLn "!"]
sequence_
is pretty easy to write yourself:
sequence_ [] = return ()
sequence_ (action:actions) = action >> sequence_ actions
There is also a sequence
(without the underscore) that runs a bunch of actions and returns their results:
main = do
ss <- sequence [readFile "foo.txt", readFile "bar.txt", readFile "baz.txt"]
-- or ss <- mapM readFile ["foo.txt", "bar.txt", "baz.txt"]
Upvotes: 5