CODEWITHSUNDEEP
java
Taolin
Taolin

Reputation: 91

How to print the output in two separate lines?

I've been trying to print the output in two separate lines, I used System.out.println() and also System.out.println("\n") but I only seem to be getting the last number I enter as the output. I'm guessing this must be easy to work around but would be grateful for a nudge in the right direction.

import java.util.Scanner;
import java.util.*;
public class StoreToArray
{
  Scanner input = new Scanner(System.in);
  ArrayList<Integer> al = new ArrayList<Integer>();
  public static void main(String args [])
  {
    //Access method using object reference        

    StoreToArray t = new StoreToArray();
    t.readFromTerminal(); 
  }

  public void readFromTerminal() {
    System.out.println("Read lines, please enter some other character to stop.");
    String in = input.nextLine();
    int check=0;
    while(true){
            check = input.nextInt();
            if(check == 0){ break;}
            al.add(check);
    }

    for (int i : al) {
        System.out.print(i);
    }
  }
}

Upvotes: 1

Views: 5221

Answers (3)

JamesB
JamesB

Reputation: 7894

The line:

String in = input.nextLine();

is capturing your first number entered and it is never added to the list al.

So, if you enter:

45

40

67

0

the output is:

[40, 67] (using System.out.println(al))

or:

4067 (using your for loop).

Note, the loop is broken by entering 0, not non-numeric characters as the first output text line would suggest.

Read lines, please enter some other character to stop

should really read

Read lines, please enter 0 to stop

[EDIT]

To add/display numbers to the list correctly:

1) Remove the line:

String in = input.nextLine();

2) Remove the for loop at the end and replace it with:

System.out.println(al);

Upvotes: 2

Sajan Chandran
Sajan Chandran

Reputation: 11487

If i understand your question correctly, may be this is what you need

public void readFromTerminal() {
    System.out
            .println("Read lines, please enter some other character to stop.");
    int check = 0;
    while (true) {
        check = input.nextInt();
        al.add(check);
        if (check == 0) {
            break;
        }

    }

    for (int i : al) {
        System.out.print(i+ "\n");
    }
}

Upvotes: 1

user1007522
user1007522

Reputation: 8118

Maybe use a do while and use try and catch. Because when you enter a character instead of a number your program is going to crash.

public class StoreToArray
{
    Scanner input = new Scanner(System.in);
    ArrayList<Integer> al = new ArrayList<Integer>();
    public static void main(String args [])
    {
        //Access method using object reference

        StoreToArray t = new StoreToArray();
        t.readFromTerminal();
    }

    public void readFromTerminal() {
        System.out.println("Read lines, please enter some other character to stop.");
        int check=0;
        do{
            try {
                check = input.nextInt();
                if(check != 0)
                  al.add(check);
            }
            catch(InputMismatchException e)
            {
                System.out.println("Failed to convert to int.");
                check = 0;
            }    
        }while(check != 0);

        for (int i : al) {
            System.out.println(i);
        }
    }
}

Upvotes: 1

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