Reputation: 647
I'm using the config var plugin for heroku (see https://devcenter.heroku.com/articles/config-vars).
It allows me to use a .env file which I do not push to source control to define the heroku environment.
So when I'm on heroku, I can access sensible information via System.properties.
In dev, I would like to read from this file so it would be best if it were on my classpath.
The .env file is at the root of my project so I cannot use something like this :
sourceSets {
main {
resources {
srcDirs = ['src/main/resources', '/']
}
}
}
What is the simplest way to include a single file into gradle resources ?
Upvotes: 8
Views: 6683
Reputation: 2189
The earlier answers seemed more complicated than I was hoping for, so I asked on the gradle forums and got a reply from a Sterling Green who's one of the gradle core devs.
He suggested configuring processResources
directly
processResources {
from(".env")
}
He also mentioned that it might be a bad idea to include the project root as an input directly.
Upvotes: 9
Reputation: 647
What I ended up doing was to add project root directory as a resource folder including only the file I was interested in :
sourceSets.main.resources { srcDir file('.') include '.env' }
Seems to do the trick. I wonder if it's the best solution thought
Upvotes: 2
Reputation: 2763
After merging the previous answer here with another tips from other sites, I came up with the following solution:
sourceSets {
specRes {
resources {
srcDir 'extra-dir'
include 'extrafiles/or-just-one-file.*'
}
}
main.resources {
srcDir 'src/standard/resources'
srcDir specRes.resources
}
}
processResources {
rename 'some.file', 'META-INF/possible-way-to-rename.txt'
}
I still wonder whether there is some better way.
Upvotes: 5