CODEWITHSUNDEEP
iosuiapplicationios8
Ed3121577
Ed3121577

Reputation: 520

Accessing the Settings app from your app in iOS 8?

Is it possible to access the settings app from your own app via a button or whatever it may be in iOS 8. I heard that it got decrepitude in iOS 5, is that true? If not did the method change in iOS 8? If there is not other way to do this what would be the best way to work around it?

Upvotes: 33

Views: 20226

Answers (4)

Daniel Storm
Daniel Storm

Reputation: 18898

Swift 3 example:

if let url = URL(string: UIApplicationOpenSettingsURLString) {
    UIApplication.shared.openURL(url)
}

Upvotes: 2

NatashaTheRobot
NatashaTheRobot

Reputation: 6949

In Swift: 

if let settingsURL = NSURL(string: UIApplicationOpenSettingsURLString) {
    UIApplication.sharedApplication().openURL(settingsURL)
}

Upvotes: 13

djibouti33
djibouti33

Reputation: 12132

As of iOS 8, it is possible to take a user from your app directly into the Settings app. They will be deep linked into your app's specific Settings page, but they can back out into the top level Settings screen.

If you're also supporting iOS 7 you'll need to check first if a specific string constant is present.

UPDATE:

If your deployment target is set to 8.0 or above, Xcode 6.3 will give you the following warning:

Comparison of address of 'UIApplicationOpenSettingsURLString' not equal to a null pointer is always true

This is because the feature was available starting in 8.0, so this pointer will never be NULL. If your deployment target is 8.0+, just remove the if statement below.

if (&UIApplicationOpenSettingsURLString != NULL) {
    NSURL *appSettings = [NSURL URLWithString:UIApplicationOpenSettingsURLString];
    [[UIApplication sharedApplication] openURL:appSettings];
}

Upvotes: 65

David Beck
David Beck

Reputation: 10159

Use UIApplicationOpenSettingsURLString.

[[UIApplication sharedApplication] openURL:[NSURL URLWithString:UIApplicationOpenSettingsURLString]];

Upvotes: 18

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