CODEWITHSUNDEEP
bashbash-completion
Maxim_united
Maxim_united

Reputation: 2003

bash completion of full path files

I've created the following bash completion function:

_scpinst ()
{
    local cur prev opts;
    COMPREPLY=();
    cur="${COMP_WORDS[COMP_CWORD]}";
    prev="${COMP_WORDS[COMP_CWORD-1]}";
    opts="-l";
    if [[ ${prev} == '-l' ]]; then
            files=$(ls /upgrade/*.tgz.gpg 2>/dev/null);
            COMPREPLY=($(compgen -W "${files}" -- ${cur}));
            compopt -o nospace
            return 0;
    fi;
    COMPREPLY=($(compgen -W "${opts}" -- ${cur}));
    return 0
}

complete -F _scpinst scpinst

It automatically completes *.tgz.gpg files in /upgrade directory after a -l flag. Is there a better way to accomplish it without using an 'ls' command. E.g. using -o filenames or -f ?

Upvotes: 3

Views: 1006

Answers (1)

Dmitry Alexandrov
Dmitry Alexandrov

Reputation: 1773

Just use -G globpat compgen’s option:

COMPREPLY=($(compgen -G "/upgrade/*.tgz.gpg" -- ${cur}));

If by some reason you want to use exactly -W wordlist (e. g. to mix filenames with something else), this is also possible:

files=(/upgrade/*.tgz.gpg)
COMPREPLY=($(compgen -W '"${files[@]}"' -- ${cur}));

Both versions should properly handle filenames containing spaces (while your variant would not).

Upvotes: 4

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