Reputation: 1189
I have a simple flask function that renders a template with a valid GeoJSON string:
@app.route('/json', methods=['POST'])
def json():
polygon = Polygon([[[0,1],[1,0],[0,0],[0,1]]])
return render_template('json.html',string=polygon)
In my json.html file, I am attempting to render this GeoJSON with OpenLayers:
function init(){
map = new OpenLayers.Map( 'map' );
layer = new OpenLayers.Layer.WMS( "OpenLayers WMS",
"http://vmap0.tiles.osgeo.org/wms/vmap0",
{layers: 'basic'} );
map.addLayer(layer);
map.setCenter(new OpenLayers.LonLat(lon, lat), zoom);
var fc = {{string}}; //Here is the JSON string
var geojson_format = new OpenLayers.Format.GeoJSON();
var vector_layer = new OpenLayers.Layer.Vector();
map.addLayer(vector_layer);
vector_layer.addFeatures(geojson_format.read(fc));
But this fails and the "
characters become '
. I have tried string formatting as seen in this question, but it didn't work.
EDIT:
I did forget to dump my json to an actual string, I'm using the geojson library so adding the function
dumps(polygon)
takes care of that, however I still can't parse the GeoJSON in OpenLayers, even though it is a valid string according to geojsonlint.com
This is the Javascript code to create a variable from the string sent from flask:
var geoJson = '{{string}}';
And here's what it looks like in the source page:
'{"type": "Polygon", "coordinates": [[[22.739485934746977, 39.26596659794341], [22.73902517923571, 39.266115931275074], [22.738329551588276, 39.26493626464484], [22.738796023230854, 39.26477459496181], [22.739485934746977, 39.26596659794341]]]}';
I am still having a problem rendering the quote characters.
Upvotes: 3
Views: 3015
Reputation: 26090
Look like you use shapely
which has http://toblerity.org/shapely/shapely.geometry.html#shapely.geometry.mapping method to create GeoJSON
-like object.
To render json
use tojson
filter which safe (see safe
filter) for latest flask versions, because jinja2
in flask
by default escape all dangerous symbols to protect XSS.
Upvotes: 1