CODEWITHSUNDEEP
pythonloopsfor-loop
Yasmin
Yasmin

Reputation: 23

Python: For loop problem

I have a simple for loop problem, when i run the code below it prints out series of 'blue green' sequences then a series of 'green' sequences. I want the output to be; if row[4] is equal to 1 to print blue else print green. 

 for row in rows:
        for i in `row[4]`:
            if i ==`1`:
                print 'blue '
            else:
                print 'green '

Any help would be grateful

thanks

Yas

Upvotes: 0

Views: 2463

Answers (3)

user177800
user177800

Reputation:

the enumerate() function will iterate and give you the index as well as the value:

for i, v in enumerate(rows):
    if i == 4:
        print "blue"
    else:
        print "green"

if you want to print blue on every fourth line else green do this:

for i, v in enumerate(rows):
    if i % 4 == 0:
        print "blue"
    else:
        print "green"

Upvotes: 2

unwind
unwind

Reputation: 400079

Try something like this:

for i in xrange(len(rows)):
  if rows[i] == '1':
    print "blue"
  else:
    print "green"

Or, since you don't actually seem to care about the index, you can of course do it more cleanly:

for r in rows:
  if r == "1":
    print "blue"
  else:
    print "green"

Upvotes: 3

Thiago Chaves
Thiago Chaves

Reputation: 9473

if rows[4] == 1:
    print 'blue'
else:
    print 'green'

Upvotes: 1

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