Reputation: 953
How can I animate fillLinearGradientColorStops
of a KineticJS Rect
? I tried using a tween but surely it doesn't work.
The rectangle:
var rect = new Kinetic.Rect({
x: 20,
y: 20,
width: 100,
height: 100,
fillLinearGradientStartPoint: { x: -50, y: -50 },
fillLinearGradientEndPoint: { x: 50, y: 50 },
fillLinearGradientColorStops: [0, 'red', 1, 'yellow']
});
The tween:
var tween = new Kinetic.Tween({
node: rect,
duration: 2,
easing: Kinetic.Easings.Linear,
fillLinearGradientColorStops: [0, 'black', 1, 'green']
});
tween.play();
Please see the fiddle http://jsfiddle.net/ZdCmS/. Is it not possible?
Upvotes: 1
Views: 328
Reputation: 20308
From there: https://github.com/ericdrowell/KineticJS/issues/901
You can use an external tweening library, like GreenSock (http://www.greensock.com/gsap-js/) with it's ColorProps plugin (http://api.greensock.com/js/com/greensock/plugins/ColorPropsPlugin.html) to tween colors and then apply them to the Kinetic shape on each frame update: http://jsfiddle.net/ZH2AS/2/
No plans for direct support of tweening color stops on a gradient fill.
var stage = new Kinetic.Stage({
container: 'container',
width: 578,
height: 200
});
var layer = new Kinetic.Layer();
var linearGradPentagon = new Kinetic.RegularPolygon({
x: 150,
y: stage.height() / 2,
sides: 5,
radius: 70,
fillLinearGradientStartPoint: {
x: -50,
y: -50
},
fillLinearGradientEndPoint: {
x: 50,
y: 50
},
fillLinearGradientColorStops: [0, 'white', 1, 'black'],
stroke: 'black',
strokeWidth: 4,
draggable: true
});
layer.add(linearGradPentagon);
stage.add(layer);
//activate ColorPropsPlugin
TweenPlugin.activate([ColorPropsPlugin]);
//object to store color values
var tmpColors = {
color0: 'white',
color1: 'black'
};
//tween the color values in tmpColors
TweenMax.to(tmpColors, 5, {
colorProps: {
color0: 'black',
color1: 'red'
},
yoyo: true,
repeat: 5,
ease:Linear.easeNone,
onUpdate: applyProps
});
function applyProps() {
linearGradPentagon.setAttrs({
fillLinearGradientColorStops: [0, tmpColors.color0, 1, tmpColors.color1]
});
layer.batchDraw();
}
Upvotes: 2