CODEWITHSUNDEEP
rubyarrayswhile-loopeach
fonz
fonz

Reputation: 329

Use Each on an array to iterate over and return the index of greater values

a = [2,2,4,8,9]
ind = 1

a.each do |x|

if a[ind] < a[x]
puts x
end

end

How can I use "each" on an array to iterate over and return the index of all values greater than a certain value in Ruby?

I would like to iterate over the given array a = [2,2,4,8,9]. I want to iterate over the entire array and, using a conditional, put out all values where a[ind] < a[x].

I receive the error comparison of fixnum nil failed. - How can I resolve this?

I did try this as well, seting a range for the process:

    a = [ 2,2,3,4,5]

x = 0
while x >= 0 && x <= 4

a.each do |x|
    if a[1] < a[x]
        puts x
    end

end
x += 1 
end

Upvotes: 0

Views: 173

Answers (3)

Darkmouse
Darkmouse

Reputation: 1939

def filtered_index(array,n)
  array.each_with_index{|e,i| puts i if e > n}
end

Upvotes: 0

Uri Agassi
Uri Agassi

Reputation: 37409

When you are iterating over an array using each the x denotes the value of the item, not its position:

a = [2,2,4,8,9]
ind = 1

a.each do |x|
  if a[ind] < x
    puts x
  end
end
# prints:
# 4
# 8
# 9

Update:

If you want to print the indexes of the elements with value greater than the value, you should use each_with_index:

a = [2,2,4,8,9]
ind = 1

a.each_with_index do |x, i|
  if a[ind] < x
    puts i
  end
end
# prints:
# 2
# 3
# 4

Upvotes: 1

J&#246;rg W Mittag
J&#246;rg W Mittag

Reputation: 369458

You want to select all elements whose index is less than themselves. You can just say exactly that in Ruby:

a.select.with_index {|el, idx| idx < el }

or even 

a.select.with_index(&:>)

Upvotes: 2

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