CODEWITHSUNDEEP
javarx-java
user3753094
user3753094

Reputation: 151

How to wait for async Observable to complete

I'm trying to build a sample using rxjava. The sample should orchestrate a ReactiveWareService and a ReactiveReviewService retruning a WareAndReview composite.

ReactiveWareService
        public Observable<Ware> findWares() {
        return Observable.from(wareService.findWares());
    }

ReactiveReviewService: reviewService.findReviewsByItem does a ThreadSleep to simulate a latency!

public Observable<Review> findReviewsByItem(final String item) {
return Observable.create((Observable.OnSubscribe<Review>) observer -> executor.execute(() -> {
    try {
        List<Review> reviews = reviewService.findReviewsByItem(item);
        reviews.forEach(observer::onNext);
        observer.onCompleted();
    } catch (Exception e) {
        observer.onError(e);
    }
}));
}

public List<WareAndReview> findWaresWithReviews() throws RuntimeException {
final List<WareAndReview> wareAndReviews = new ArrayList<>();

wareService.findWares()
    .map(WareAndReview::new)
.subscribe(wr -> {
        wareAndReviews.add(wr);
        //Async!!!!
        reviewService.findReviewsByItem(wr.getWare().getItem())
            .subscribe(wr::addReview,
                throwable -> System.out.println("Error while trying to find reviews for " + wr)
            );
    }
);

//TODO: There should be a better way to wait for async reviewService.findReviewsByItem completion!
try {
    Thread.sleep(3000);
} catch (InterruptedException e) {}

return wareAndReviews;
}

Given the fact I don't want to return an Observable, how can I wait for async Observable (findReviewsByItem) to complete?

Upvotes: 14

Views: 49322

Answers (3)

akarnokd
akarnokd

Reputation: 70007

Most of your example can be rewritten with standard RxJava operators that work together well:

public class Example {

    Scheduler scheduler = Schedulers.from(executor);

    public Observable<Review> findReviewsByItem(final String item) {
        return Observable.just(item)
               .subscribeOn(scheduler)
               .flatMapIterable(reviewService::findReviewsByItem);
    }
    public List<WareAndReview> findWaresWithReviews() {
        return wareService
               .findWares()
               .map(WareAndReview::new)
               .flatMap(wr -> {
                   return reviewService
                          .findReviewsByItem(wr.getWare().getItem())
                          .doOnNext(wr::addReview)
                          .lastOrDefault(null)
                          .map(v -> wr);
               })
               .toList()
               .toBlocking()
               .first();
    }
}

Whenever you want to compose services like this, think of flatMap first. You don't need to block for each sub-Observable but only at the very end with toBlocking() if really necessary.

Upvotes: 18

theBuckWheat
theBuckWheat

Reputation: 17

Another way would be to declare a CountdownLatch before starting. Then call countDown() on that latch in your onCompleted(). You can then replace your Thread.sleep() with await() on that latch.

Upvotes: -5

Marek Hawrylczak
Marek Hawrylczak

Reputation: 2504

You may use methods from BlockingObservable see https://github.com/Netflix/RxJava/wiki/Blocking-Observable-Operators. e.g 

BlockingObservable.from(reviewService.findReviewsByItem(..)).toIterable()

Upvotes: 14

Related Questions