CODEWITHSUNDEEP
java
user3749995
user3749995

Reputation: 21

how do you initialize a variable that is declared?

if (eyeColor == green)
{
    System.out.println ("If your eyes are green I recommend buying .... ");
    ....
}

error says

variable green might not have been initialized

I can't display my whole code since it is for school, but I am just wondering how can I initialized it if the eyeColor from the user input (using scanner) is green?

Upvotes: 0

Views: 90

Answers (3)

robzillaDev
robzillaDev

Reputation: 91

Initialise eyeColor before you compare it. If it is a string, simply initialise it as an empty string:

String eyeColor;
eyeColor = "";

Before you perform any checks to see what eyeColor has been specified, you may also want to check to make sure that is is NOT still ""..

Upvotes: 1

Mike Elofson
Mike Elofson

Reputation: 2037

Assuming that your variable eyeColor is the input from the user. You could use the following

if("green".equals(eyeColor))

Since green is a string, and it will never change (it is always green), you can just use the string. It is also worth noting that in Java, you need to use .equals() when comparing string values, not '=='.

I would also suggest using .toLowerCase(), so that the comparison is no longer case sensitive. An example check is shown in the code below:

public static void main(String args[]) throws IOException {

    String eyeColor = "Green";
    if("green".equals(eyeColor.toLowerCase())){
        System.out.println ("If your eyes are green I recommend buying .... ");
    }

}

Upvotes: 0

Juned Ahsan
Juned Ahsan

Reputation: 68715

Not sure what is the type of green but this is how you declare method local variables:

Object green = null;

or

Object green = SOME_DEFAULT_VALUE_BETTER_THAN_NULL;

Upvotes: 1

Related Questions