CODEWITHSUNDEEP
iosswift
junyi00
junyi00

Reputation: 792

iOS Swift max(), min()

In Swift, I am trying to use the max() and min() functions.

max<T : Comparable>(x: T, y: T, rest: T...) -> T
min<T : Comparable>(x: T, y: T, rest: T...) -> T

I am trying to use the max() function in this way:

var paddleX: Int = Int(paddle.position.x) + Int(location.x - previousLocation.x)
max(paddleX, paddle.frame.x/2, nil)

but I am getting this error:

Cannot convert the expression's type of '()' to type 'NilType'

Is the nil causing this problem? What is rest: T... supposed to be?

Upvotes: 24

Views: 25686

Answers (2)

possen
possen

Reputation: 9276

You can use the empty parameters for simple comparable data types, if you have a more complex data structures you need to provide a closure. Note: the order of the comparison are the following for both max and min if you do it backward you get wrong results.

[(0, "a"), (2, "b"), (5, "f"), (6, "g")].min(by: {$0.0 < $1.0}) // min (0, "a")
[(0, "a"), (2, "b"), (5, "f"), (6, "g")].max(by: {$0.0 < $1.0}) // max (6, "g")

Upvotes: 0

anisoptera
anisoptera

Reputation: 1108

Don't pass anything at all there. It's a variadic function, you can call it with two or more parameters.

Upvotes: 35

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