CODEWITHSUNDEEP
cenumstypedefc99
stdcerr
stdcerr

Reputation: 15598

enum type not available

I'm having problems with an enum type. I have the following in my header:

enum map_type_t{
    MAP_TYPE_PORT,
    MAP_TYPE_VLAN,
    MAP_TYPE_L2MAC,
    MAC_TYPE_VPWS,
    MAC_TYPE_BFD,
    MAC_TYPE_VPLS
};

I included the header in my C file and that's eherre I have a prototype like int store_to_flash (map_type_t map_type, void* pData) but now, for some reason, the type map_type_t isn't being recognized, why not I'm wondering? I've also tried to typedef the enum instead but couldn't get that working either, it looked like:

typedef enum {
    MAP_TYPE_PORT,
    MAP_TYPE_VLAN,
    MAP_TYPE_L2MAC,
    MAC_TYPE_VPWS,
    MAC_TYPE_BFD,
    MAC_TYPE_VPLS
}map_type_t;

What's the problem, I don't understand.

PS: this is with the diab compiler in C99 mode

edit 1

interesting, if I move

typedef enum map_type_e {
    MAP_TYPE_PORT,
    MAP_TYPE_VLAN,
    MAP_TYPE_L2MAC,
    MAC_TYPE_VPWS,
    MAC_TYPE_BFD,
    MAC_TYPE_VPLS
}map_type_t;

from my header into the C file on the very top, after my includes it seems to work just fine... now that's odd isn't it? Any idea why that might be?

Upvotes: 0

Views: 122

Answers (1)

Keith Thompson
Keith Thompson

Reputation: 263237

The declaration

enum map_type_t { /* ... */ };

creates a type named enum map_type_t. The identifier map_type_t is a tag, not a type name.

You can either use a typedef to create an alias for the type, or you can refer to it by its name enum map_type_t. (The typedef in your question should have worked; we'd have to see more code to know why it didn't work for you.)

Similar rules apply to struct and union type declarations.

(The rules are different in C++.)

Upvotes: 2

Related Questions