Reputation: 2892
I am dealing with very strange issue of dealing with garbage in iterating through variable which has been cast to an array
$arr = (array)$var; // problem
$arr = array($var); // ok
The first method seems to work fine on values with integers, but not with strings. Is there any documented difference and does php have real
casting ?
The problem is with lavarel 4, Database sources, function on line 704
Upvotes: 0
Views: 139
Reputation: 214949
If $var
is a scalar, it's documented that both lines do the same:
For any of the types: integer, float, string, boolean and resource, converting a value to an array results in an array with a single element with index zero and the value of the scalar which was converted. In other words, (array)$scalarValue is exactly the same as array($scalarValue).
http://www.php.net/manual/en/language.types.array.php#language.types.array.casting
Upvotes: 1
Reputation: 9261
There are two ways to cast a variable in PHP as a specific type.
More Info : http://www.electrictoolbox.com/type-casting-php/
Upvotes: 0