CODEWITHSUNDEEP
c#asp.netdatatable
Vignesh Subramanian
Vignesh Subramanian

Reputation: 7289

Getting count of all repeated rows in a datatable in C#

I am filling a dataset by running a stored procedure, and i am filling a datatable from the dataset.

DataSet RawDataSet = DataAccessHelper.RunProcedure("storedprocedureName");
//this will just return the dataset by running the procedure
DataTable RankTable = RawDataSet.Tables[0];

The Datatable has the below values:

Vicky   Login   6/24/2014
Vicky   Login   6/25/2014
Arun    Game    6/26/2014
Arun    Login   6/27/2014
Kumar   Login   6/28/2014
Kumar   Game    6/29/2014
Arun    Login   6/30/2014
Arun    Login   7/1/2014
Kumar   Game    7/2/2014
Vicky   Login   7/3/2014
Arun    Login   7/4/2014
Arun    Game    7/5/2014

I want to parse this dataTable and get how many times everyone has done an action, i.e how many times each row is repeated:

Vicky   Login  3
Arun    Game   2
Arun    Login  4
Kumar   Login  1
Kumar   Game   2

I am new to C#. This can be done using count(*) in SQL but I need to do this using C#. Please let me know if there are any ways to achieve this.

I have searched SO but all posts are related to removing the duplicates/finding the duplicates, which does not solve my purpose.

Upvotes: 3

Views: 4355

Answers (1)

Habib
Habib

Reputation: 223277

You can achieve that using LINQ like:

var query = RankTable.AsEnumerable()
                    .GroupBy(r => new { Name = r.Field<string>("Name"), Action = r.Field<string>("Action") })
                    .Select(grp => new
                    {
                        Name = grp.Key.Name,
                        Action = grp.Key.Action,
                        Count = grp.Count()
                    });

Here Name is assumed to be the column name for first column, and Action is assumed to be name of second column which has values like login, game etc.

You may see LINQ to DataSet - MSDN

For output use:

foreach (var item in query)
{
    Console.WriteLine("Name: {0}, Action: {1}, Count: {2}",item.Name, item.Action,item.Count);
}

Upvotes: 6

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