CODEWITHSUNDEEP
phpdatedatetime
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Reputation: 8593

How to convert 2014-06-24T22:33:49.180Z format into Y-m-d H:i:s in PHP

I received Fatal error: Call to a member function format() on a non-object error when I tried to use format on a json converted date string of 2014-06-24T22:37:13.151Z (specifically from new Date() )

$objData->myCodeCreateDate="2014-06-24T22:39:34.652Z"
$date = DateTime::createFromFormat('j-M-Y', $objData->myCodeCreateDate);
echo $date->format('Y-m-d H:i:s');

Upvotes: 0

Views: 2776

Answers (1)

Aeveus
Aeveus

Reputation: 5382

That looks like the way Amazon sends back its timestamp, which follows this format in UTC time:

Y-m-d\TH:i:s.u\Z.

You can edit your createFromFormat format to the above, and it should work.

Here's an example with your data:

$date_string = "2014-06-24T22:37:13.151Z";
$date_object = DateTime::createFromFormat('Y-m-d\TH:i:s.u\Z', $date_string);
echo $date_object->format('Y-m-d H:i:s');

Upvotes: 4

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