CODEWITHSUNDEEP
pythonpython-2.7tuples
guagay_wk
guagay_wk

Reputation: 28088

How to compare these 2 python tuple of tuples of unequal length and output another tuple based on the comparison?

I have this tuple of tuples;

Tup1= ( ('AAA', 2), ('BBB', 3) )

I have another tuple;

Tup2 = ('AAA', 'BBB', 'CCC', 'DDD')

I want to compare Tup1 and Tup2. Based on the comparison, I want to create another tuple of tuples that look like this;

OutputTup = ( ('AAA', 2), ('BBB', 3), ('CCC', 0), ('DDD', 0) )

The logic is like this. Look into every element inside Tup2 and then look for matching element in Tup1. If there is matching element(example 'AAA') in Tup1, copy to OutputTup ('AAA', 2). If there is no matching element (example 'CCC'), then assign a value of 0 and append to OutputTup ('CCC', 0).

How can this be done in Python 2.7? Thanks.

Upvotes: 0

Views: 778

Answers (2)

sundar nataraj
sundar nataraj

Reputation: 8702

for some extend .please edit my answer . i cannot figure how to check type. if some one know feel free to edit my answer

from itertools import izip,izip_longest
Tup1= ( ('AAA', 2), ('BBB', 3) )
Tup2 = ('AAA', 'BBB', 'CCC', 'DDD')
lis=[ i if type(i[0])==type(0) else i[0] for i in list(izip_longest(Tup1, Tup2 , fillvalue=0))]



#output [('AAA', 2), ('BBB', 3), (0, 'CCC'), (0, 'DDD')]

Upvotes: 2

yoopoo
yoopoo

Reputation: 363

This also works with the output you want:

tup1 = ( ('AAA', 2), ('BBB', 3) )
tup2 = ('AAA', 'BBB', 'CCC', 'DDD')
dic = dict( tup1 )
for tri in tup2:
    dic[tri] = dic.get(tri,0)

print tuple(dic.items()) 
#(('AAA', 2), ('BBB', 3), ('CCC', 0), ('DDD', 0))

Upvotes: 3

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