Reputation: 21
I can successfully bind a DataTable to a GridView by auto generating columns, but I need to display a multi-lined cell for one of the columns. To do this, I want to use a template field with an item template using a TextBox object. I fill in the DataTable by adding columns and then adding the rows. I know my datatable is set up right because it shows all the data (except for the multi-lined cell) as I want it. My issue is getting the gridview to extract my data based on the column names and filling in the template fields I have set up. If I turn AutoGenerateColumns off then the 4 templatefield columns still appear (in the correct amount according to the datatable too), just blank, and if I have it set to true, then the 4 blank columns appear as well as 4 additional columns with the same headers that contain my data using the defaults for what the cell contains to display the information.
<asp:GridView ID="DataGrid1" runat="server" AutoGenerateColumns="False" HeaderStyle-BorderStyle="None" CellPadding="3" ItemStyle-Wrap="true" >
<Columns>
<asp:TemplateField HeaderText="Code">
<asp:ItemTemplate>
<asp:Label ID="txtCode" runat="server" Text='<%# Eval("Code") %>'>
</asp:Label>
</asp:ItemTemplate>
</asp:TemplateField>
<asp:TemplateField HeaderText="Title">
<asp:ItemTemplate>
<asp:Label ID="txtTitle" runat="server" Text='<%# Eval("Title") %>'>
</asp:Label>
</asp:ItemTemplate>
</asp:TemplateField>
<asp:TemplateField HeaderText="Class">
<asp:ItemTemplate>
<asp:Label ID="txtClass" runat="server" Text='<%# Eval("Class") %>'>
</asp:Label>
</asp:ItemTemplate>
</asp:TemplateField>
<asp:TemplateField HeaderText="History">
<asp:ItemTemplate>
<asp:TextBox ID="txtHistory" runat="server" IsReadOnly="true" Text='<%# Eval("History")%>'>
</asp:TextBox>
</asp:ItemTemplate>
</asp:TemplateField>
</Columns>
</asp:GridView>
The above is the portion of my asp.net code that relates to the GridView in question. Following is how i set up my DataTable and bind it.
DataTable table = new DataTable();
table.Columns.Add("Code", typeof(string));
table.Columns.Add("Title", typeof(string));
table.Columns.Add("Class", typeof(string));
table.Columns.Add("History", typeof(string));
for (int i = 0; i < index; i++)
{
table.Rows.Add(docs[i].Code, docs[i].Name, docs[i].Class.Name, history[i]);
}
DataGrid1.DataSource = table;
DataGrid1.DataBind();
Upvotes: 2
Views: 20801
Reputation: 3
foreach (GridViewRow grdRow in grdMenuPermitted.Rows)
{
DataRow drow = dt.NewRow();
Label lblMenuName = (Label)grdRow.FindControl("lblMenuName");
HiddenField hdnID = (HiddenField)grdRow.FindControl("hdnID");
drow["MenuName"] = lblMenuName.Text;//grdRow.Cells[0].Text;
drow["MenuID"] = hdnID.Value;
//drow["lname"] = grdRow.Cells[3].Text;
dt.Rows.Add(drow);
}
Upvotes: -1
Reputation: 2898
Change .aspx code like below
<Columns>
<asp:TemplateField HeaderText="Code">
<ItemTemplate>
<asp:Label ID="txtCode" runat="server" Text='<%# Eval("Code") %>'>
</asp:Label>
</ItemTemplate>
</asp:TemplateField>
<asp:TemplateField HeaderText="Title">
<ItemTemplate>
<asp:Label ID="txtTitle" runat="server" Text='<%# Eval("Title") %>'>
</asp:Label>
</ItemTemplate>
</asp:TemplateField>
<asp:TemplateField HeaderText="Class">
<ItemTemplate>
<asp:Label ID="txtClass" runat="server" Text='<%# Eval("Class") %>'>
</asp:Label>
</ItemTemplate>
</asp:TemplateField>
<asp:TemplateField HeaderText="History">
<ItemTemplate>
<asp:TextBox ID="txtHistory" runat="server" IsReadOnly="true"
Text='<%# Eval("History")%>'>
</asp:TextBox>
</ItemTemplate>
</asp:TemplateField>
</Columns>
Upvotes: 4