CODEWITHSUNDEEP
javajava.util.scannerinputmismatchexception
Francesco Riccio
Francesco Riccio

Reputation: 78

Java InputMismatchException error. What causes it?

What is the reason why that the following Java procedure causes a InputMismatchException error?

import java.util.Scanner;
public class Main {
    public static void main(String[] args) {
        String input = "hello 12345\n";
        Scanner s = new Scanner(input);
        s.next("hello ");
    }
}

Thank you

Upvotes: 0

Views: 524

Answers (1)

Kevin Bowersox
Kevin Bowersox

Reputation: 94429

This is occurring because hello[space] is not a token in the String. The String is being tokenized by a whitespace delimiter so the tokens are as follows:

String input = "hello 12345\n";
Scanner s = new Scanner(input);

while(s.hasNext()){
    System.out.println(s.next());
}
//Outputs: Hello
//         12345

The error message is simply telling you that it cannot find hello[space] amongst the tokens, which are hello and 12345.

If you want to find the pattern regardless of delimiters use, String#findInLine:

s.findInLine("hello ");

Upvotes: 1

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