Reputation: 307
I'm trying to sort the results of a jQuery selection with tSort.
HTML:
<div sort="2"></div>
<div sort="3"></div>
<div sort="1"></div>
<div sort="4"></div>
<div sort="6"></div>
<div sort="5"></div>
Javascript:
<script>
$sort_order = $('div').tsort({attr:'sort'});
</script>
I want the result to be: 1,2,3,4,5,6 in the jQuery object, not yet inserted into the page. Is this possible with tSort, or should I write my own algorithm?
Upvotes: 3
Views: 2891
Reputation: 7060
It is easier to do it if there is a wrapper of all the div
elements.
HTML:
<div id="wrapper">
<div sort="2">2</div>
<div sort="3">3</div>
<div sort="1">1</div>
<div sort="4">4</div>
<div sort="6">6</div>
<div sort="5">5</div>
</div>
Javascript (with jQuery):
var $wrapper = $('#wrapper');
$wrapper.find('div').sort(function (a, b) {
return +a.getAttribute('sort') - +b.getAttribute('sort');
})
.appendTo($wrapper);
In response to @Tim's comment, you can place the elements that do not have the sort
attributes at the back of the wrapper
element easily, even without jQuery.
Assuming that this is your HTML:
<div id="wrapper">
<div style="color:red;">red color, without sort attribute</div>
<div style="color:red;" sort="7">red color (sort attribute=7)</div>
<div sort="2">2</div>
<div sort="3">3</div>
<div sort="1">1</div>
<div sort="4">4</div>
<div sort="6">6</div>
<div sort="5">5</div>
</div>
You can place the element(s) that do not have the sort
attribute by having this as your Javascript:
// As shown earlier above,
var $wrapper = $('#wrapper');
$wrapper.find('div').sort(function (a, b) {
return +a.getAttribute('sort') - +b.getAttribute('sort');
})
.appendTo($wrapper);
// New code to add:
var divs = document.getElementsByTagName('div');
for(var i = 0; i < divs.length; i++) {
if(divs[i].getAttribute('sort') == null || divs[i].getAttribute('sort') == undefined) {
divs[i].parentNode.appendChild(divs[i]);
}
}
Upvotes: 2