Reputation: 8277
I have to pass what exception occured in one function to a slot inside a different class.
_qObject = QtCore.QObject()
except Exception, ex:
QtCore.QObject.emit(_qObject, QtCore.SIGNAL("error_occured"))
I want to pass ex to class that has
QtCore.QObject.connect(_qObject, QtCore.SIGNAL("error_occured"), self.__errorOccured)
This is my case
from PyQt4.QtCore import pyqtSignal, pyqtSlot
from PyQt4.QtGui import QWidget, QApplication
has_error = pyqtSignal(Exception)
class SomeOtherClass(QWidget):
# this is my UI class
def __init__(self, parent=None):
super(SomeOtherClass, self).__init__(parent)
# Initialise the Class and connect signal to slot
has_error.connect(self.thrown_error)
@pyqtSlot(Exception)
def thrown_error(self, my_err):
#Do Stuff with the Exception
print(type(my_err), my_err)
self.close()
def makeError():
try:
print 1/0
except ZeroDivisionError, ze:
has_error.emit(ze)
app = QApplication([])
SomeOtherClass()
Upvotes: 1
Views: 784
Reputation: 8277
How Shadow9043 suggested is also right but in comments things got twisted but this is what I found the correct and simplistic approach.
Long Story in Short!!!
except Exception, ex:
QtCore.QObject.emit(_qObject, QtCore.SIGNAL("error_occured"), str(ex))
and in the class where I connect this exception
i will take this ex string as argument
def __errorOccured(self, exStr):
print exStr
Here is how I have it working, if anyone has got better suggestion in how I achieved it please comment.
from PyQt4.QtCore import pyqtSignal, pyqtSlot
from PyQt4.QtGui import QWidget, QApplication
from PyQt4 import QtCore
import sys
_qObject = QtCore.QObject()
class SomeOtherClass(QWidget):
# this is my UI class
def __init__(self, parent=None):
super(SomeOtherClass, self).__init__(parent)
# Initialise the Class and connect signal to slot
QtCore.QObject.connect(_qObject, QtCore.SIGNAL("error_occured"), self.thrown_error)
def thrown_error(self, my_err):
#Do Stuff with the Exception
print(type(my_err), my_err)
def makeError():
try:
print 1/0
except ZeroDivisionError, ex:
QtCore.QObject.emit(_qObject, QtCore.SIGNAL("error_occured"), str(ex))
app = QApplication(sys.argv)
win = SomeOtherClass()
makeError()
win.show()
sys.exit(app.exec_())
Upvotes: 0
Reputation: 2260
See below code for example:
from PyQt4.QtCore import pyqtSignal, pyqtSlot
from PyQt4.QtGui import QWidget, QApplication
import sys
class SomeClass(QWidget):
# Declare a new signal - passes Exception
has_error = pyqtSignal(Exception)
def __init__(self, parent=None):
super(SomeClass, self).__init__(parent)
def run_something(self):
#Force an Error
try:
1 / 0
except ZeroDivisionError as ze:
#Emit the Signal
self.has_error.emit(ze)
class SomeOtherClass(QWidget):
def __init__(self, parent=None):
super(SomeOtherClass, self).__init__(parent)
# Initialise the Class and connect signal to slot
class1 = SomeClass()
class1.has_error.connect(self.thrown_error)
class1.run_something()
@pyqtSlot(Exception)
def thrown_error(self, my_err):
#Do Stuff with the Exception
print(type(my_err), my_err)
app = QApplication(sys.argv)
SomeOtherClass()
See the new way to connect signals to slots
Upvotes: 2