CODEWITHSUNDEEP
pythonc++swig
Crazymooner
Crazymooner

Reputation: 241

how can I get a char*[] from python

I use swig wrapped some c++ api function. There is one function, the interface is f(char*[] strs).

How can I pass a valid parameter to this function. This is what I did. 

str = ["str","str2"]
f(str)

it will throw error

TypeError: in method 'f', argument 1 of type 'char *[]

Upvotes: 1

Views: 190

Answers (1)

Oliver
Oliver

Reputation: 29473

SWIG does not convert arrays to Python lists automatically. Since you are using C++, use std::string and std::vector for your f, then SWIG will make all the necessary conversions automatically (don't forget to include "std_vector.i" and such, see the SWIG docs):

void f(std::vector<std::string> > strs)

If you cannot modify the declaration of f, you can create an %inline wrapper in the .i: 

%inline {
    void f(const std::vector<std::string> >& strs) 
    {
        // create tmpCharArray of type char*[] from strs
        const char* tmpCharArray[] = new const char* [strs.size()];
        for (i=0; i<strs.size(); i++) 
              tmpCharArray[i] = strs[i].c_str();
        f(tmpCharArray);
        delete[] tmpCharArray;
     }
}

Upvotes: 1

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