CODEWITHSUNDEEP
c#htmlasp.net-mvc-5
Cristian Simionescu
Cristian Simionescu

Reputation: 80

I am getting an System.NullReferenceException error I cannot understand

I am getting this error:

"An exception of type 'System.NullReferenceException' occurred in App_Web_lmzivtl2.dll but was not handled in user code. Additional information: Object reference not set to an instance of an object."

And here is the code I was using: 

    @model IEnumerable<PtExamen.Models.Teste>

   @{
       ViewBag.Title = "Teste";
       Layout = "~/Views/Shared/_Layout.cshtml";
   }

   <h2>Teste</h2>
    @{foreach (var item in Model )
    {
       <p>
          &nbsp     @Html.Raw(ViewBag.Descriere)  <br> <br>
          &nbsp &nbsp  <a href="@ViewBag.NumeFisier" target="_blank">@ViewBag.test</a>)                                
       </p>
   }
   }

I do not understand why this error came to be since i have used similar examples of this so far and I did not get this problem. Any help, explanation would be great. Thanks in advance!

I used something similar elsewhere and this error did not take place and I cant really find what made this part of the code not cause any problems and the other did. Here is another place I used something similar but I did not have any problems:

@model IEnumerable<PtExamen.Models.Capitole>
@{
    ViewBag.Title = "Index";
    Layout = "~/Views/Shared/_Layout.cshtml";
}




<div>
    <div id="div-1">
     <p><h2> @ViewBag.MateriaSelectata.ToUpper()</h2></p>
    </div>

    <div id="div-1a">

            @foreach (var item in Model)
            {
                string materiasel = ViewBag.MateriaSelectata;
                int cidSelectat = Convert.ToInt32(ViewBag.cidSelectat);
               <p>@Html.ActionLink(item.den_capitol, "Index", new { materia = item.disciplina , cid = item.id }) <br></p>

Upvotes: 1

Views: 26165

Answers (1)

BurtonMuriuki
BurtonMuriuki

Reputation: 151

Somewhere in your dll (App_Web_lmzivtl2.dll) you referencing a null object or you forgot to instantiate it. i.e object myobject=new object(); then give myobject a value.

Upvotes: 6

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