CODEWITHSUNDEEP
javaspringurl
user2907217
user2907217

Reputation: 137

Required String parameter error on spring

I am getting Required String parameter error if the value contains %, Could you please let me know why this is happening and a solution for this

For example if my url is localhost:8080/getsearchresult?searchparam=test it works

But if pass % in url, spring gives me error

localhost:8080/getsearchresult?searchparam=%

then getting error and error is Required String parameter searchparam

Could you please let me know the reason behind this and would be great if suggest some solution for this

Upvotes: 0

Views: 102

Answers (1)

Luiggi Mendoza
Luiggi Mendoza

Reputation: 85779

What you have here is an incomplete URL. % is a special symbol used in URL encoding:

URL encoding replaces unsafe ASCII characters with a "%" followed by two hexadecimal digits

Not only that, but % itself is an unsafe ASCII.

If you want to try sending % as URL parameter, use %25:

localhost:8080/getsearchresult?searchparam=%25

Upvotes: 2

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