CODEWITHSUNDEEP
pythonplotbokeh
quasiben
quasiben

Reputation: 1464

Disable scientific notation on axes using Bokeh

How can you disable scientific output of numbers on an axis in bokeh? For example, I want 400000 and not 4.00e+5

In mpl: ax.get_xaxis().get_major_formatter().set_scientific(False)

Upvotes: 26

Views: 11904

Answers (4)

rahulv88
rahulv88

Reputation: 131

I was trying to turn off scientific notation from a logarithmic axis, and the above answers did not work for me.

I found this: python bokeh plot how to format axis display

In that spirit, this worked for me:

from bokeh.models import BasicTickFormatter

fig = plt.figure(title='xxx', x_axis_type='datetime',y_axis_type='log')
fig.yaxis.formatter = BasicTickFormatter(use_scientific=False)

Upvotes: 7

Josh Sherick
Josh Sherick

Reputation: 2161

Note that as of Bokeh v0.9.1, Marek's answer will no longer work due to changes in the interface for Charts. The following code (from GitHub) is a fully-functional example of how to turn off scientific notation in a high level chart.

from bokeh.embed import components
from bokeh.models import Axis
from bokeh.charts import Bar
data = {"y": [6, 7, 2, 4, 5], "z": [1, 5, 12, 4, 2]}
bar = Bar(data)
yaxis = bar.select(dict(type=Axis, layout="left"))[0]
yaxis.formatter.use_scientific = False
script, div = components(bar)
print(script)
print(div)

The key lines are:

yaxis = bar.select(dict(type=Axis, layout="left"))[0]
yaxis.formatter.use_scientific = False

Upvotes: 4

Marek
Marek

Reputation: 885

To disable the scientific output in Bokeh, use use_scientific attribute of the formatter you use.

You can find more information regarding use_scientific attribute here:

Example (originaly comes from Bokeh issues discussion):

from bokeh.models import Axis
yaxis = bar.chart.plot.select(dict(type=Axis, layout="left"))[0]
yaxis.formatter.use_scientific = False
bar.chart.show()

Upvotes: 4

korst1k
korst1k

Reputation: 499

You can disable scientific notation with this:

fig = plt.figure(title='xxx', x_axis_type='datetime')
fig.left[0].formatter.use_scientific = False

Upvotes: 26

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