CODEWITHSUNDEEP
javainterfacecharsequence
user3799927
user3799927

Reputation: 35

Instantiating a interface CharSequence

CharSequence[] items = { “Google”, “Apple”, “Microsoft” };

if CharSequence is an interface then, in the above example aren't we instantiating a interface?

Upvotes: 3

Views: 994

Answers (3)

user3790568
user3790568

Reputation: 311

CharSequence[] items = { “Google”, “Apple”, “Microsoft” };

Here only the declared type of the reference variable is an interface, which is alright.

But the objects in the array are String objects - whose class implements the CharSequence interface.

Say, CharSequence[] items = { new Charsequence() } would result in compilation error

whereas

CharSequence[] items = { new someclass() }

where

class someclass implements CharSequence {

//

}

is totally fine

Upvotes: -1

Nikhil Talreja
Nikhil Talreja

Reputation: 2774

Here is a similar example using custom classes:

interface A{}

class A1 implements A{}

class A2 implements A{}

class A3 implements A{}

public class B {

    A[] items = {new A1(),new A2(), new A3()};

}

Here each object in items is actually of the implementing type (A1,A2,A3) rather than A itself.

In your example something like this would also have been possible:

CharSequence[] items = {"Google",new StringBuffer("Apple"), new StringBuilder("Microsoft")};

Upvotes: 0

Robby Cornelissen
Robby Cornelissen

Reputation: 97322

You're instantiating a String array and then assigning it to variable that has a CharSequence array type. This works because String is assignable to (implements) CharSequence. Here's a couple more examples:

CharSequence cs = "Whatever";
List<Integer> list = new ArrayList<>();

So you're actually instantiating concrete types and assigning them to a variable/field that has an interface type.

Upvotes: 2

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