user2424370
user2424370

Reputation:

Looping JSON objects and plot to map

I am trying to loop through returned JSON objects and plot a heatmap based on the x and y coordinates. Here is how I set up my heatmap:

function getHeatMap() {
heatLayer = new HeatmapLayer({
    config: {
        "useLocalMaximum": true,
        "radius": 40,
        "gradient": {
            0.45: "rgb(000,000,255)",
            0.55: "rgb(000,255,255)",
            0.65: "rgb(000,255,000)",
            0.95: "rgb(255,255,000)",
            1.00: "rgb(255,000,000)"
        }
    },
    "map": map,
    "domNodeId": "heatLayer",
    "opacity": 0.85
});

$.ajax({
    url: "index.aspx/getBusCommuter",
    type: "POST",
    data: "",
    contentType: "application/json; charset=utf-8",
    dataType: "json",
    success: function (data) {
        var parsed = JSON.parse(data.d);
        var data = [];
        $.each(parsed, function (i, jsondata) {
            var coordXicon = jsondata.BusStopX;
            var coordYicon = jsondata.BusStopY;

            data = [
                {
                    attributes: {},
                    geometry: {
                        spatialReference: { wkid: 102100 },
                        type: "point",
                        x: coordXicon,
                        y: coordYicon
                    }
                }
           ];
        });
        heatLayer.setData(data);
        map.addLayer(heatLayer);
    },
    error: function (request, state, errors) {
    }
});

}

Basically the JSON object will just loop to the last set of JSON objects and plot out only the last set instead of all. I wonder which part of my logic was wrong.

Thanks in advance.

Upvotes: 0

Views: 139

Answers (1)

Alexis King
Alexis King

Reputation: 43842

The issue is here:

data = [
    {
        attributes: {},
        geometry: {
            spatialReference: {
                wkid: 102100
            },
            type: "point",
            x: coordXicon,
            y: coordYicon
        }
    }
];

You are setting the entire data array for each item (overwriting all the old data) when you probably just want to push a new element onto the end. Try this instead:

data.push({ ... });

Upvotes: 1

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