Reputation: 23
I tried to fit my data with a gaussian curve using nls. Because that didn't work, i tried to make an easy example to see what goes wrong:
>x=seq(-4,4,0.1)
>y=2*dnorm(x-0.4,2)+runif( length(x) , min = -0.01, max = 0.01)
>df=data.frame(x,y)
>m <- nls(y ~ k*dnorm(x-mu,sigma), data = df, start = list(k=2,mu=0.4,sigma=2))
Error in nlsModel(formula, mf, start, wts, upper) : singular gradient
matrix at initial parameter estimates
> m <- nls(y ~ k*dnorm(x-mu,sigma), data = df, start == list(k=1.5,mu=0.4,sigma=2))
Error in nlsModel(formula, mf, start, wts, upper) : singular gradient
matrix at initial parameter estimates
Why doesn't this work?
Upvotes: 1
Views: 2541
Reputation: 269441
First please use set.seed
to make your example reproducible. Second I think you meant dnorm(x, 0.4, 2)
and not dnorm(x-0.4, 2)
. These are not the same since in the x-0.4 case the mean of x-0.4
is 2
and in the other case the standard devaiation is 2
. If we make this change then it works:
set.seed(123)
x=seq(-4,4,0.1)
y=2*dnorm(x, 0.4, 2)+runif( length(x) , min = -0.01, max = 0.01)
df=data.frame(x,y)
nls(y ~ k*dnorm(x, mu,sigma), data = df, start = list(k=2,mu=0.4,sigma=2))
giving:
Nonlinear regression model
model: y ~ k * dnorm(x, mu, sigma)
data: df
k mu sigma
2.0034 0.3914 2.0135
residual sum-of-squares: 0.002434
Number of iterations to convergence: 2
Achieved convergence tolerance: 5.377e-06
Upvotes: 1