Reputation: 12487
So I have this code from a previous question: http://jsfiddle.net/928Dj/4/
$("ul.opt").addClass("hidden");
$('#filter > li > a').on("click", function(e) {
$(this).next('ul').toggle();
});
I was wondering if anyone could tell me how I allow it to still be toggled open and closed, but also make it so if one menu is open and I click to open another menu, it closes the first one, meaning only one menu can be open at any time.
Upvotes: 0
Views: 97
Reputation: 1190
This is the best way. You can also try this:
$("ul.opt").addClass("hidden");
$('#filter > li > a').on("click", function(e) {
$(this).next('ul').toggle();
$(this).parent().siblings().find('.opt').hide();
});
Upvotes: 0
Reputation: 43156
You can hide all the visible submenus before showing the current one as follows
$("ul.opt").addClass("hidden");
$('#filter > li > a').on("click", function(e) {
var ul = $(this).next('ul');
$('ul li ul:visible').not(ul).hide();
ul.toggle();
});
Upvotes: 1
Reputation: 9637
Try to hide the opened ul
elements first and then toggle
the current element,
$("ul.opt").addClass("hidden");
$('#filter > li > a').on("click", function (e) {
var cache = $(this).next('ul');
$('#filter ul:visible').not(cache).hide();
cache.toggle();
});
Upvotes: 1