CODEWITHSUNDEEP
python
navyad
navyad

Reputation: 3860

Place decimal before last two digits for an integer

I have a interger value like:

99990

I want this value to be converted into like:

999.90

Regardless of the length of the number, I need to display the number with 2 decimal places at the end, and I'd like to do it in an efficient way. The purpose is to display money amount.

Upvotes: 0

Views: 2736

Answers (6)

user2555451
user2555451

Reputation:

You can use format here:

>>> n = 99990
>>> format(n / 100, '.02f')
'999.90'
>>>

The result needs to be a string because Python automatically removes the trailing 0 with numbers:

>>> n = 99990
>>> n / 100
999.9
>>>

For those who are still using Python 2.x, you will need to divide the number by a float:

>>> n = 99990
>>> format(n / 100.0, '.02f')
'999.90'
>>>

Upvotes: 1

Dave
Dave

Reputation: 1208

yet another way,

str(99990 * 0.01) + '0'

Upvotes: -1

darkcharl
darkcharl

Reputation: 58

Dividing with a float 100. value should covert it into a float. After that, it's only a matter of formatting to display it the way you like.

$ python
Python 2.7.6 (default, Mar 22 2014, 22:59:56)
[GCC 4.8.2] on linux2
Type "help", "copyright", "credits" or "license" for more information.
>>> number = 99990
>>> print("{0:.2f}".format(number / 100.))
999.90

Upvotes: 0

TheSoundDefense
TheSoundDefense

Reputation: 6935

This will work quickly and easily.

print "%.2f" % (99990 / 100.0)

Upvotes: 0

chepner
chepner

Reputation: 530922

With an integer value, you can use divmod to produce separate dollar and cent components.

dollars, cents = divmod(value, 100)
print("{0}.{1}".format(dollars, cents))

Upvotes: 4

DeeTee
DeeTee

Reputation: 707

word = 99990
wordString = str(word)[0:-2] + "." + str(word)[-2:]
print(wordString)

Here's a little code snippet that will word, it converts the number to the string

Upvotes: -1

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