Reputation: 3723
I am Compiling My string Code(I read My Code from Text File) In vb and it works fine but i have a function that returns nullable double(Double?)
when i use it like this
Dim x As Double? = Myfunc(1000) 'it returns Nothing
my x variable fills with Nothing and it's ok
But When I use it like this
Dim x = Myfunc(1000) 'it returns Nothing
my x value is 0 !!!!
How can i solve this problem i want my users write codes like first code block
i tested all Option Explicit and Option Strict but it did not gain me anything.
please let me know how can i use Just dim x not Dim x as (type) thank you for your helps
UPDATE :this is Myfunc Code :
Function Myfunc(parameterId As Long) As Double?
If parameterId = 1000 Then
Return Nothing
Else
Return tot(parameterId) 'it is a dictionary of values
End If
End Function
And this Is my Compile Class :
Private Shared Function Compile(ByVal vbCode As String) As CompilerResults
Dim providerOptions = New Dictionary(Of String, String)
providerOptions.Add("CompilerVersion", "v4.0")
' Create the VB.NET compiler.
Dim vbProv = New VBCodeProvider(providerOptions)
' Create parameters to pass to the compiler.
Dim vbParams = New CompilerParameters()
' Add referenced assemblies.
vbParams.ReferencedAssemblies.Add("mscorlib.dll")
vbParams.ReferencedAssemblies.Add("System.Core.dll")
vbParams.ReferencedAssemblies.Add("System.dll")
vbParams.ReferencedAssemblies.Add("System.Windows.Forms.dll")
vbParams.ReferencedAssemblies.Add("System.Data.dll")
vbParams.ReferencedAssemblies.Add("Microsoft.VisualBasic.dll")
vbParams.ReferencedAssemblies.Add("System.Xml.dll")
vbParams.ReferencedAssemblies.Add("System.Xml.Linq.dll")
vbParams.GenerateExecutable = False
' Ensure we generate an assembly in memory and not as a physical file.
vbParams.GenerateInMemory = True
' Compile the code and get the compiler results (contains errors, etc.)
Return vbProv.CompileAssemblyFromSource(vbParams, vbCode)
End Function
Upvotes: 0
Views: 300
Reputation: 672
As discussed above, Option Infer On
needs to be included to force the compiler to create the variable as the required type - in this case the Double?
returned by MyFunc
.
Upvotes: 2