CODEWITHSUNDEEP
c#asp.net-mvcmodelbindersactionmethod
Karl
Karl

Reputation: 659

ASP.NET MVC - POST Action Method with Additional Parameters from URL

With ASP.net MVC is it possible to POST a form to a controller action which includes parameters not in the form, but from the URL?

For example

The Action method in GroupController:

    [AcceptVerbs(HttpVerbs.Post)]
    public ActionResult Create(int idOne, int idTwo, Model model)
    { ... }

The route:

"{controller}/{action}/{idOne}/{idTwo}"

Posted URL:

/Employee/Show/1/42

In this example, the form is being posted to a different controller, the model has the correct value, however the other parameters have default values 0.

The behavior I was expecting is that the ModelBinder would see that I have two parameters that match the given route, and assign the current values of 1 and 42 to the parameters in the same same way a GET operation works.

Is this behavior not supported, or am I missing something?

EDIT: To be clear, the form on the Show view for the controller Employee contains a form which is posting to a different controller. We can call it Group.

The form action URL looks like this

/Groups/Create/0/0

The form is declared as follows

Html.BeginForm("Create", "Groups")

After trying many different overloads for Html.BeginForm I have found that the parameters are only mapped when the form action URL matches the current URL in the browser address bar.

So if i navigate to the URL /Groups/Create/1/42 I will have a new form. If I then submit the form, the URL route values are passed to the POST action.

Upvotes: 11

Views: 35596

Answers (5)

Ilya Sulimanov
Ilya Sulimanov

Reputation: 7856

I had a similar problem, the configuration RouteConfig has solved this problem.

public class RouteConfig
    {
        public static void RegisterRoutes(RouteCollection routes)
        {
             ...
             routes.MapRoute(
             "MyRoute",
             "{controller}/{action}/{idOne}/{idTwo}",
             new
             {
                 controller = "Employee", // as an example
                 action = "Show",
                 idOne = UrlParameter.Optional,
                 idTwo= UrlParameter.Optional
             }, new { idOne = @"\d{1,5}" });

        }
    }

...And... Html.BeginRouteForm()

@using (Html.BeginRouteForm("MyRoute", new { idOne = 1, idTwo= 2 }, FormMethod.Post))

Writes an opening tag to the response. When the user submits the form, the request will be processed by the route target. This member is overloaded. For complete information about this member, including syntax, usage, and examples, click a name in the overload list.

And all works

Upvotes: 1

Romias
Romias

Reputation: 14133

Once you get to your Create view, your route values used to get there need to be re-posted to the post action.

So, one option is having a pair of hiddens, to hold the ids that came from the route. This way, once you post the formas, its values are posted along with the other inputs.

Upvotes: 0

Mickey Puri
Mickey Puri

Reputation: 889

I recently had this issue too, and because I had a different route, it was mapping to the default route, without taking into account the extra route params that I was passing in.

So to get it working quickly, I wrote the form using form tags instead, and used @Url.Action to create the required action.

Upvotes: 0

Brandon Linton
Brandon Linton

Reputation: 4411

I'm pretty sure that you can only post form data from inputs inside the form. Have you considered rendering the view in such a way to create form input values off of the URL (perhaps with an HTML helper?).

UPDATE: If you don't want to use the form at all, use ControllerContext.RouteData.Values["idOne"] as opposed to passing it in through the method signature.

Upvotes: 2

Jørn Schou-Rode
Jørn Schou-Rode

Reputation: 38376

If I understand your question correctly, you want the action of the rendered <form> element pointing to URL containing route values. This should be possible with one of the overloads of the HtmlHelper.BeginForm() extension method:

Html.BeginForm("action","controller", new { idOne=1, idTwo=2 }, FormMethod.Post);

Let me know if I got your question all wrong :)

Upvotes: 10

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