CODEWITHSUNDEEP
c++arrays
G.K.
G.K.

Reputation: 33

Need to find the number of contents in the array

I have a char array and I want to find out the number of contents in it. For example, my array is:

char myArray[10];

And after input it's content is:

ABC

Now I want to store in a variable 'size', the size of the area related to content. So, in this case:

size = 3

How do I find that?

Upvotes: 0

Views: 53

Answers (4)

ugene
ugene

Reputation: 146

defining array as char myArray[10]; will not always initialize it's content to zeros, so depending on how you fill it with ABC you either can or cannot find the corect lenght. In worst case regular strlen() will always report numbers >10, or even result in read access vialation. I try initialize it like char myArray[10] = {}; first

Upvotes: 0

Wasim Thabraze
Wasim Thabraze

Reputation: 810

Try this:

int len = strlen(myArray).

strlen is a part of stdlib.h library. Don't forget to declare it in your program.

Upvotes: 0

Shashwat Kumar
Shashwat Kumar

Reputation: 5287

strlen(myArray) is what you want.

Upvotes: 1

Thomas Russell
Thomas Russell

Reputation: 5980

A naive way of doing this would be to look for the null-terminating character \0, this is already implemented for you in the C-function strlen, so there are two ways of doing this:

int StringLength( const char* str, int maxLength )
{
     for( int i = 0; i < maxLength; ++i )
     {
          if( str[i] == '\0' )
              return i;
     }

     return -1;
}

Or you could just call strlen as follows:

int iLength = strlen( myArray );

However, as you have tagged this , the best way to do this would be to not deal with C-style character arrays and instead use the extremely useful std::string class.

Upvotes: 3

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