I am having some difficulties with an awk statement in my bash code

Question

I am trying to check if certain values (DIC, IC, RNDIC) are in a text file's first row but not in the first column. Sew below for all the detail. Not that each field in the text file is tabulated.

file.txt

NO   DIC   IC   RNDIC   FI   BO   CF
---
1    2    3    4    5    6

This is the code I have to deal with this file:

type=$(awk 'NR==1 {
   for (i = 1; i <= NF; i++) 
   {
      if (i != 1 && ($i == "DIC" || $i == "IC" || $i == "RNDIC")) 
         print "1"   
   }  
}' $PWD/file.txt)

if [[ $type == "1" ]]; then
   # rest of the code is irrelevant
fi

echo $type

The problem is that it never enters the if statement after $type is initialized. The reason is because $type is actually 1 1 instead of 1. I realize the mistake I made is with the if statment in the for loop but don't know how to fix it. Any suggestions? Thanks.

Let me know if further explanation is required.

Answer 1

No need to fork and rely on awk if you're using bash:

read -ra FIELDS < "$PWD/file.txt"
for A in "${FIELDS[@]:1}"; do
    case "$A" in
    DIC|IC|RNDIC)
        # <do some things>
        break
        ;;
    esac
done

Or

function is_type1 {
    local FIELDS A
    read -ra FIELDS < "$1"
    for A in "${FIELDS[@]:1}"; do
        case "$A" in
        DIC|IC|RNDIC)
            return 0
            ;;
        esac
    done
    return 1
}

if is_type1 "$PWD/file.txt"; then
    # <do some things>
fi

Note: I just used case since I don't know the version of bash and extglob may be a hassle.

Answer 2

You can call exit after printing 1 once:

type=$(awk 'NR==1 {
   for (i = 1; i <= NF; i++) {
      if (i != 1 && ($i == "DIC" || $i == "IC" || $i == "RNDIC")) {
         print "1"
         exit
      }
   }  
}' $PWD/file.txt)