Reputation: 19612
I want to diplay the Memory usage, Disk Usage and CPU Load in the following format:
Memory Usage: 33/512MB (6%)
Disk usage: 4.2/20GB (23%)
CPU Load: 0.01
So I started using the below script to do that but somehow it gives me an error
#!/bin/bash
free -m | awk 'NR==2{printf "Memory Usage: %s/%sMB (%.2f%)\n", $3,$2,$3*100/$2 }'
df -h | awk '$NF=="/"{printf "Disk Usage: %d/%dGB (%s)\n", $3,$2,$5}'
top -bn1 | grep load | awk '{printf "CPU Load: %.2f\n", $(NF-2)}'
Below is the error I get -
awk: run time error: not enough arguments passed to printf("Memory Usage: %s/%sMB (%.2f%)
")
FILENAME="-" FNR=2 NR=2
I am running ubuntu 12.04. Any idea what's wrong?
Update:-
After running my below shell script -
#!/bin/bash
free -m | awk 'NR==2{printf "Memory Usage: %s/%sMB (%.2f%%)\n", $3,$2,$3*100/$2 }'
df -h | awk '$NF=="/"{printf "Disk Usage: %d/%dGB (%s)\n", $3,$2,$5}'
top -bn1 | grep load | awk '{printf "CPU Load: %.2f\n", $(NF-2)}'
I got below output -
Memory Usage: 128504/128896MB (99.70%)
Disk Usage: 3/48GB (8%)
CPU Load: 0.40
Does CPU Load looks ok? What does 0.40 means? And what number I should say will be high for CPU Load?
Upvotes: 4
Views: 15472
Reputation: 212228
Try escaping the %
:
printf "Memory Usage: %s/%sMB (%.2f%%)\n"
Upvotes: 3