Reputation: 4229
How to get graph for each column of data.frame within one plot with loop? Must be easy just can't figure it out.
Sample data:
rdata <- data.frame(y=rnorm(1000,2,2),v1=rnorm(1000,1,1),v2=rnorm(1000,3,3),
v3=rnorm(1000,4,4),v4=rnorm(1000,5,5))
What I have tried?
library(lattice)
p <- par(mfrow=c(2,2))
for(i in 2:5){
w <- xyplot(y~rdata[,i],rdata)
print(w)
}
par(p)
Upvotes: 1
Views: 6062
Reputation: 206536
Inorder to easily arrange a bunch of lattice plots, I like to use the helper function print.plotlist. It has a layout=
parameter that acts like the layout()
function for base graphics. For example, you could call
rdata <- data.frame(y=rnorm(1000,2,2),v1=rnorm(1000,1,1),v2=rnorm(1000,3,3),
v3=rnorm(1000,4,4),v4=rnorm(1000,5,5))
library(lattice)
plots<-lapply(2:5, function(i) {xyplot(y~rdata[,i],rdata)})
print.plotlist(plots, layout=matrix(1:4, ncol=2))
to get
Otherwise you normally use a split=
parameter to the print statement to place a plot in a subsection of the device. For example, you could also do
print(plots[[1]], split=c(1,1,2,2), more=T)
print(plots[[2]], split=c(1,2,2,2), more=T)
print(plots[[3]], split=c(2,1,2,2), more=T)
print(plots[[4]], split=c(2,2,2,2))
Upvotes: 3
Reputation: 7928
If you don't have to use lattice
you can just use base plot
instead and it should work as you want.
p <- par(mfrow=c(2,2))
for(i in 2:5){
plot(y~rdata[,i],rdata)
}
par(p)
If you want to use lattice
look this answer. Lattice ignores par
, so you have to do some more work to achieve what you want.
Upvotes: 3