Reputation: 15
Hopefully there isn't a duplicated question that I've looked over because I've been scouring this forum for someone who has posted to a similar to the one below...
Basically, I've created a python script that will scrape the callsigns of each ship from the url shown below and append them into a list. In short it works, however whenever I iterate through the list and display each element there seems to be a '[' and ']' between each of the callsigns. I've shown the output of my script below:
Output
*********************** Contents of 'listOfCallSigns' List ***********************
0 ['311062900']
1 ['235056239']
2 ['305500000']
3 ['311063300']
4 ['236111791']
5 ['245639000']
6 ['235077805']
7 ['235011590']
As you can see, it shows the square brackets for each callsign. I have a feeling that this might be down to an encoding problem within the BeautifulSoup library.
Ideally, I want the output to be without any of the square brackets and just the callsign as a string.
*********************** Contents of 'listOfCallSigns' List ***********************
0 311062900
1 235056239
2 305500000
3 311063300
4 236111791
5 245639000
6 235077805
7 235011590
This script I'm using currently is shown below:
My script
# Importing the modules needed to run the script
from bs4 import BeautifulSoup
import urllib2
import re
import requests
import pprint
# Declaring the url for the port of hull
url = "http://www.fleetmon.com/en/ports/Port_of_Hull_5898"
# Opening and reading the contents of the URL using the module 'urlib2'
# Scanning the entire webpage, finding a <table> tag with the id 'vessels_in_port_table' and finding all <tr> tags
portOfHull = urllib2.urlopen(url).read()
soup = BeautifulSoup(portOfHull)
table = soup.find("table", {'id': 'vessels_in_port_table'}).find_all("tr")
# Declaring a list to hold the call signs of each ship in the table
listOfCallSigns = []
# For each row in the table, using a regular expression to extract the first 9 numbers from each ship call-sign
# Adding each extracted call-sign to the 'listOfCallSigns' list
for i, row in enumerate(table):
if i:
listOfCallSigns.append(re.findall(r"\d{9}", str(row.find_all('td')[4])))
print "\n\n*********************** Contents of 'listOfCallSigns' List ***********************\n"
# Printing each element of the 'listOfCallSigns' list
for i, row in enumerate(listOfCallSigns):
print i, row
Does anyone know how to remove the square brackets surrounding each callsign and just display the string?
Thanks in advance! :)
Upvotes: 0
Views: 130
Reputation: 485
Change the last lines to:
# Printing each element of the 'listOfCallSigns' list
for i, row in enumerate(listOfCallSigns):
print i, row[0] # <-- added a [0] here
Alternatively, you can also add the [0]
here:
for i, row in enumerate(table):
if i:
listOfCallSigns.append(re.findall(r"\d{9}", str(row.find_all('td')[4]))[0]) <-- added a [0] here
The explanation here is that re.findall(...)
returns a list (in your case, with a single element in it). So, listOfCallSigns
ends up being a "list of sublists each containing a single string":
>>> listOfCallSigns
>>> [ ['311062900'], ['235056239'], ['311063300'], ['236111791'],
['245639000'], ['305500000'], ['235077805'], ['235011590'] ]
When you enumerate
your listOfCallSigns
, the row
variable is basically the re.findall(...)
that you appended earlier in the code (that's why you can add the [0]
after either of them).
So row
and re.findall(...)
are both of type "list of string(s)" and look like this:
>>> row
>>> ['311062900']
And to get the string inside the list, you need access its first element, i.e.:
>>> row[0]
>>> '311062900'
Hope this helps!
Upvotes: 3
Reputation: 335
This can also be done by stripping the unwanted characters from the string like so:
a = "string with bad characters []'] in here"
a = a.translate(None, "[]'")
print a
Upvotes: 0