CODEWITHSUNDEEP
listrmatrix
andrewj
andrewj

Reputation: 3035

converting a matrix to a list

Suppose I have a matrix foo as follows:

foo <- cbind(c(1,2,3), c(15,16,17))

> foo
     [,1] [,2]
[1,]    1   15
[2,]    2   16
[3,]    3   17

I'd like to turn it into a list that looks like

[[1]]
[1]  1 15

[[2]]
[1]  2 16

[[3]]
[1]  3 17

You can do it as follows:

lapply(apply(foo, 1, function(x) list(c(x[1], x[2]))), function(y) unlist(y))

I'm interested in an alternative method that isn't as complicated. Note, if you just do apply(foo, 1, function(x) list(c(x[1], x[2]))), it returns a list within a list, which I'm hoping to avoid.

Upvotes: 12

Views: 15725

Answers (3)

GKi
GKi

Reputation: 39647

You can use asplit to split a matrix into a list.

asplit(foo, 1)
#[[1]]
#[1]  1 15
#
#[[2]]
#[1]  2 16
#
#[[3]]
#[1]  3 17

Upvotes: 1

hadley
hadley

Reputation: 103898

library(plyr)
alply(foo, 1)

Upvotes: 6

Shane
Shane

Reputation: 100154

Here's a cleaner solution:

as.list(data.frame(t(foo)))

That takes advantage of the fact that a data frame is really just a list of equal length vectors (while a matrix is really a vector that is displayed with columns and rows...you can see this by calling foo[5], for instance).

You could also do this, although it isn't much of an improvement:

lapply(1:nrow(foo), function(i) foo[i,])

Upvotes: 20

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