Reputation: 43
I'm in search of a SUMPRODUCT formula, or a similar sort of formula which does the same thing. It should do the following:
EDIT: Added point 3.
I'll add an image to visualize what I mean. Hopefully someone can help me!
Upvotes: 1
Views: 282
Reputation: 71578
With some helper columns, you could use something like this (open in new tab for larger version):
The formulae:
In B2 to remove spaces and hence get a 'clean' ZIP and check the length:
=IF(LEN(SUBSTITUTE(A2," ",""))=6,SUBSTITUTE(A2," ",""),"")
In C2, to get the sum:
=IFERROR(IF(AND(ISNUMBER(LEFT(B2,4)*1),CODE(MID(LOWER(B2),5,1))>=97,CODE(MID(LOWER(B2),5,1))<=122,CODE(RIGHT(LOWER(B2)))>=97,CODE(RIGHT(LOWER(B2)))<=122),SUMPRODUCT($H$2:$K$8*($G$2:$G$8=B2)),""),"")
In G2, I used the same one as in B2:
=IF(LEN(SUBSTITUTE(F2," ",""))=6,SUBSTITUTE(F2," ",""),"")
Without the helper, the formula becomes much longer because of repeating parts:
=IFERROR(IF(AND(LEN(SUBSTITUTE(A2," ",""))=6,ISNUMBER(LEFT(SUBSTITUTE(A2," ",""),4)*1),CODE(MID(LOWER(SUBSTITUTE(A2," ","")),5,1))>=97,CODE(MID(LOWER(SUBSTITUTE(A2," ","")),5,1))<=122,CODE(RIGHT(LOWER(SUBSTITUTE(A2," ",""))))>=97,CODE(RIGHT(LOWER(SUBSTITUTE(A2," ",""))))<=122),SUMPRODUCT($H$2:$K$8*(SUBSTITUTE($F$2:$F$8," ","")=SUBSTITUTE(A2," ",""))),""),"")
Or
=IFERROR(
IF(
AND(
LEN(SUBSTITUTE(A2," ",""))=6, ' Check length
ISNUMBER(LEFT(SUBSTITUTE(A2," ",""),4)*1), ' Check numbers
CODE(MID(LOWER(SUBSTITUTE(A2," ","")),5,1))>=97, ' Check if letter
CODE(MID(LOWER(SUBSTITUTE(A2," ","")),5,1))<=122, ' Check if letter
CODE(RIGHT(LOWER(SUBSTITUTE(A2," ",""))))>=97, ' Check if letter
CODE(RIGHT(LOWER(SUBSTITUTE(A2," ",""))))<=122 ' Check if letter
),
SUMPRODUCT(
$H$2:$K$8*
(SUBSTITUTE($F$2:$F$8," ","")=SUBSTITUTE(A2," ",""))),
""
),
""
)
Oops, forgot that IFERROR
was not in 2003. The only reason why I used it was that MID
would return an empty string and CODE
would subsequently give an error. You can use the below instead which makes sure the string is 6 chars first:
=IF(LEN(SUBSTITUTE(A2," ",""))=6,IF(AND(ISNUMBER(LEFT(SUBSTITUTE(A2," ",""),4)*1),CODE(MID(LOWER(SUBSTITUTE(A2," ","")),5,1))>=97,CODE(MID(LOWER(SUBSTITUTE(A2," ","")),5,1))<=122,CODE(RIGHT(LOWER(SUBSTITUTE(A2," ",""))))>=97,CODE(RIGHT(LOWER(SUBSTITUTE(A2," ",""))))<=122),SUMPRODUCT($H$2:$K$8*(SUBSTITUTE($F$2:$F$8," ","")=SUBSTITUTE(A2," ",""))),""),"")
Upvotes: 3
Reputation: 556
Here you have a formula to validate Dutch postal codes
=AND(LEN(A2)=6; ISNUMBER(VALUE(LEFT(A2;4))); CODE(MID(LOWER(A2);5;1)) >= 97; CODE(MID(LOWER(A2);5;1)) <= 122; CODE(MID(LOWER(A2);6;1)) >= 97; CODE(MID(LOWER(A2);6;1)) <= 122)
0-9 = ASCII code 48 to 57
a-z = ASCII code 97 to 122 (lowercase)
In case you have a Dutch version of Excel, the formula would be:
=EN(LENGTE(A2)=6; ISGETAL(WAARDE(LINKS(A2;4))); CODE(DEEL(KLEINE.LETTERS(A2);5;1)) >= 97; CODE(DEEL(KLEINE.LETTERS(A2);5;1)) <= 122; CODE(DEEL(KLEINE.LETTERS(A2);6;1)) >= 97; CODE(DEEL(KLEINE.LETTERS(A2);6;1)) <= 122)
Upvotes: 1