CODEWITHSUNDEEP
pythonsimulationsimpy
Alarr
Alarr

Reputation: 121

Release of resources in SimPy in a different function to where it was requested

In a simulation I would like to able to request a resource in one function before calling another function in which the resource is released. When I use the method shown below it doesn’t work and I get an error. Thanks in advance.

(in function 1):

req = resource.request()
yield req

yield.env.process(function2( ))

(in function 2):

resource.release(req)

Is this possible? Let me know what else if any other information is required.

Upvotes: 1

Views: 913

Answers (1)

Stefan Scherfke
Stefan Scherfke

Reputation: 3232

From you’re example it’s not clear why it would not work. The simulation below works as expected:

import simpy


def func1(name, env, res):
    req = res.request()
    yield req
    print(name, 'got resource at', env.now)
    yield env.process(func2(name, env, res, req))
    print(name, 'done')


def func2(name, env, res, req):
    yield env.timeout(1)
    yield res.release(req)
    print(name, 'released at', env.now)


env = simpy.Environment()
res = simpy.Resource(env, capacity=1)
env.process(func1('A', env, res))
env.process(func1('B', env, res))
env.run()

The output:

A got resource at 0
A released at 1
A done
B got resource at 1
B released at 2
B done

Upvotes: 2

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