CODEWITHSUNDEEP
python
alphanumeric
alphanumeric

Reputation: 19349

How to remove sub-directory name from filepath

dirpath variable points to a directory with two sub-folders both named 'Temp':

dirpath='C:/Users/Temp/AppData/Local/Temp'

Another variable word stores the name of directory that needs to removed from dirpath but only if it is a last sub-folder:

word='temp'

So the final result should be:

result='C:/Users/Temp/AppData/Local'

Please note the "Temp" in dirpath starts with uppercase. While the word variable defines 'temp' in lower case. The final result should preserve original upper case characters used in dirpath variable .

How to achieve this with a minimum code?

Upvotes: 0

Views: 117

Answers (3)

rch
rch

Reputation: 101

You should try to work with the "os" module.

In particular to the following two functions:

os.path.join() and os.path.split()

If you use os.path.split() then you can use os.path join to get the final path when you remove the last component of the list. In your case the first split would give you what you want.

>>> import os
>>> dirpath='C:/Users/Temp/AppData/Local/Temp'
>>> dirpath
'C:/Users/Temp/AppData/Local/Temp'
>>> os.path.split(dirpath)
('C:/Users/Temp/AppData/Local', 'Temp')
>>> result = os.path.split(dirpath)
>>> result[0]
'C:/Users/Temp/AppData/Local'
>>>

Upvotes: 2

alphanumeric
alphanumeric

Reputation: 19349

dirpath='C:/Users/Temp/AppData/Local/Temp'
word='temp'

if dirpath.lower().endswith(word.lower()):
    dirpath=dirpath[:-(len(word)+1)]

Upvotes: 0

Gregor
Gregor

Reputation: 1375

Use the regular expression module re

import re
dirpath = 'C:/Users/Temp/AppData/Local/Temp'
word = 'temp'

if re.search("/%s$"%word, dirpath.lower()):
    dirpath = dirpath[:-len(word)] 

print dirpath

Maybe you combine this with the first answer, I'm not that good with the os-module

Upvotes: 0

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