CODEWITHSUNDEEP
bashshell
Vercingetorix
Vercingetorix

Reputation: 111

Exclude files in a shell script that has a certain pattern

I need to create a shell script that create thumbnails of files in a certain directory, but exclude those that already is created. The original files is named using a five digit number .jpg. Eg. 13993.jpg. Th thumbnails is named 13993_thumb.jpg. The code below is what i have started with bu I am not able to find the matching pattern... Any suggestions?

 #!/bin/bash
 for i in *.jpg
 do
 echo "Prcoessing image $i ..."
 [[ $i == "0-9_thumb.jpg"* ]]  && continue
 # /usr/bin/convert -thumbnail 200 $i thumb.$i
 done

Upvotes: 0

Views: 990

Answers (2)

paq
paq

Reputation: 180

Better use the power of utils and pipes:

$ ls *.jpg
11223.jpg  12345_thumb.jpg  42424.jpg  99999_thumb.jpg
$ ls *.jpg | grep -v '^[0-9]\{5\}_thumb\.jpg' | while read f; do echo convert $f ... ; done
convert 11223.jpg ...
convert 42424.jpg ...

Regular expression in your case:

[[ "12345_thumb.jpg" =~ ^[0-9]{5}_thumb\.jpg$ ]]

Upvotes: 1

anubhava
anubhava

Reputation: 784888

You are not using correct glob pattern.You need to use:

[[ "$i" == [0-9]*"_thumb.jpg" ]] && continue
  1. Character class [0-9]* will match 1 or more digits
  2. Glob pattern should not be in the quotes only literal text needs to be in quotes

Upvotes: 0

Related Questions