CODEWITHSUNDEEP
pythonnumpymatplotlibnetworkx
user2498497
user2498497

Reputation: 703

Fast way to convert an array of integers to color strings or color values in python

I am trying to plot data points according to their class labels. 

import numpy
import matplotlib as plt
x = numpy.random.uniform(size = [1, 15])
labels = numpy.array([1,2,2,2,2,1,1,2,3,1,3,3,1,1, 3])
plt.plot(x, 'o', c = labels)

When I did the above, Python complained that the color values need to be 0, 1. Then I used

plt.plot(x, 'o', c = labels/max(labels))

There is no error generated. A plot window pops up, but there is nothing in the plot window. I am wondering what is the correct way to define the colors that are according to the data labels?

I am also trying to color nodes according to the class labels. This is done in networkx. A simple example is:

import networkx as nx
G=nx.complete_graph(5)
nx.draw(G, node_col = node_labels)

The array node_labels will be the labels of the 5 vertices. I tried using the same approaches I tried above, but the network always has red nodes.

Any insight will be appreciated. Thanks!

Upvotes: 3

Views: 6509

Answers (2)

Matt Ellis
Matt Ellis

Reputation: 530

In order to do what you're seeking, your labels array must be a floating-point array. From the look of it, [labels] is being interpreted as a integer array. Thus, modify your code as follows to achieve the desired result. 

plt.plot(x, 'o', c = labels)

should be changed to: 

plt.plot(x, 'o', c = labels.astype(numpy.float)

Stay awesome!!

Upvotes: 0

user2304916
user2304916

Reputation: 8144

Since your labels are integers you can use them as an index for a list of colors:

colors = ['#e41a1c', '#377eb8', '#4daf4a']

then, using scatter is simpler than plot since you can provide a list/sequence of colors:

labels = np.random.randint(low=0, high=3, size=20)
plt.scatter(np.random.rand(20), np.random.rand(20), color=np.array(colors)[labels])

Which will give you this:

enter image description here

To get nice colors you can use colorbrewer.

Upvotes: 3

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