CODEWITHSUNDEEP
rubyarraysrange
Napoleon
Napoleon

Reputation: 1102

Array with range values?

a = [1, 2, 3..9, 10, 15, 20..43]
print a.include?(5) # Returns false

I was expecting it to return true, but 3..9 is not translated to [3,4,5,6,7,8,9].

I am missing something silly but I can't figure it out. Basically I want to initialize it with both regular fixnums and ranges.

Upvotes: 1

Views: 132

Answers (3)

fbonetti
fbonetti

Reputation: 6672

If you would like a "lazier" approach that doesn't require you to convert ranges into array elements, try using the === (case equality) operator.

a = [1, 2, 3..9, 10, 15, 20..43]
a.any? { |x| x === 5 }

I recommend using this approach since it's far more efficient than splatting the range into separate elements.

Upvotes: 3

Santhosh
Santhosh

Reputation: 29124

Another solution, without splat.

a = [1, 2, 3..9, 10, 15, 20..43]

a.any? {|i| i.kind_of?(Range) ? i.include?(5) : i == 5 }
# => true

Upvotes: 1

Arup Rakshit
Arup Rakshit

Reputation: 118271

You have to splat it

a = [1, 2, *3..9, 10, 15, 20..43]
a.include?(5) # => true

Upvotes: 7

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