CODEWITHSUNDEEP
shrenamefile-extension
TheGeoEngineer
TheGeoEngineer

Reputation: 97

How to delete part of a filename using bash script

I need to rename all filenames (of varying lengths) in directory that end in ".dat.txt" to just ".txt"

INPUT:

FOO.dat.txt, FOO2.dat.txt, SPAM.dat.txt, SPAM_AND_EGGS.dat.txt

DESIRED OUTPUT:

FOO.txt, FOO2.txt, SPAM.txt, SPAM_AND_EGGS.txt

Have been trying to use "rename" but I've never used for this situation before.

for f in DIRECTORY'/'*.dat.txt
    do
        rename 's/*.dat.txt/*.txt' *
    done

Thanks for your help!!!

Upvotes: 3

Views: 3658

Answers (3)

JKillian
JKillian

Reputation: 18331

Assuming you have the rename program from the util-linux package installed: 

rename .dat.txt .txt *.dat.txt

But I think you might have the perl version instead:

rename 's/\.dat\.txt/\.txt/' *.dat.txt

See this Linux Questions wiki page for a brief summary of the two versions.

Upvotes: 3

rje
rje

Reputation: 6418

for i in FOO*dat.txt; do mv "$i" "${i%%dat.txt}txt"; done

Using bash parameter expansion: http://wiki.bash-hackers.org/syntax/pe#substring_removal

Or perhaps more elegantly:

for i in *dat.txt; do mv "$i" "${i/dat.txt/txt}"; done

Upvotes: 1

etr
etr

Reputation: 1262

This should work:

for old in FOO*.dat.txt
do
new=$(echo $old | sed 's/.dat.txt/.txt/g')
mv "$old" "$new"
done

Upvotes: 2

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