CODEWITHSUNDEEP
c++loops
Gold
Gold

Reputation: 33

Coin Flip C++ Loop

I'm trying to make a coin flipper in c++. The point of it is to have the coin "flip" 100 times, and display the amount of times it was heads or tails.

For example: "The coin has been flipped 100 times. Heads = 68 Tails = 32

Here's my code so far:

#include <iostream>
#include <random>

int main()

{
    using namespace std;

    random_device rd;

    default_random_engine random(rd());
    uniform_int_distribution<int> uniform_dist(1, 2);

    int coin;
    int heads = 0;
    int tails = 0;

    coin = uniform_dist(random);

    cout << "I will flip this coin 100 times.";
    cout << "I will then print the results.";

    while (coin != 100)

How can I "flip" the coin 100 times and how would I go about making a loop for the coin?

Upvotes: 0

Views: 1781

Answers (2)

R Sahu
R Sahu

Reputation: 206567

I am not sure why a loop is hard for you but this should work.

for ( int count = 0; count != 100; ++count )
{
   int coin = uniform_dist(random);
   if ( coin == 1 )
   {
      ++heads;
   }
   else
   {
      ++tails;
   }
}

Upvotes: 0

dcatteeu
dcatteeu

Reputation: 501

There is no need for a loop. What you want is a random number drawn from a binomial distribution:

std::binomial_distribution<int> distribution(100,0.5);
int heads = distribution(random);
int tails = 100 - heads;

See http://www.cplusplus.com/reference/random/binomial_distribution/ and http://en.wikipedia.org/wiki/Binomial_distribution for more information.

Upvotes: 2

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