CODEWITHSUNDEEP
phpdownload
Farukest
Farukest

Reputation: 1518

How to show file size when force the browser to download in PHP

I'm downloading mp4,mp3 etc.. files from my server with php. But browsers are not showing the size of file. I searched everywhere but i couldn't find any working answer. Hope you can help me. Thanks in advance.

Here is the code :

  function force_download($file)
 {
 $ext = explode(".", $file);
 switch($ext[sizeof($ext)-1])
{
  case 'jar': $mime = "application/java-archive"; break;
  case 'zip': $mime = "application/zip"; break;
  case 'jpeg': $mime = "image/jpeg"; break;
  case 'jpg': $mime = "image/jpg"; break;
  case 'jad': $mime = "text/vnd.sun.j2me.app-descriptor"; break;
  case "gif": $mime = "image/gif"; break;
  case "png": $mime = "image/png"; break;
  case "pdf": $mime = "application/pdf"; break;
  case "txt": $mime = "text/plain"; break;
  case "doc": $mime = "application/msword"; break;
  case "ppt": $mime = "application/vnd.ms-powerpoint"; break;
  case "wbmp": $mime = "image/vnd.wap.wbmp"; break;
  case "wmlc": $mime = "application/vnd.wap.wmlc"; break;
  case "mp4s": $mime = "application/mp4"; break;
  case "ogg": $mime = "application/ogg"; break;
  case "pls": $mime = "application/pls+xml"; break;
  case "asf": $mime = "application/vnd.ms-asf"; break;
  case "swf": $mime = "application/x-shockwave-flash"; break;
  case "mp4": $mime = "video/mp4"; break;
  case "m4a": $mime = "audio/mp4"; break;
  case "m4p": $mime = "audio/mp4"; break;
  case "mp4a": $mime = "audio/mp4"; break;
  case "mp3": $mime = "audio/mpeg"; break;
  case "m3a": $mime = "audio/mpeg"; break;
  case "m2a": $mime = "audio/mpeg"; break;
  case "mp2a": $mime = "audio/mpeg"; break;
  case "mp2": $mime = "audio/mpeg"; break;
  case "mpga": $mime = "audio/mpeg"; break;
  case "wav": $mime = "audio/wav"; break;
  case "m3u": $mime = "audio/x-mpegurl"; break;
  case "bmp": $mime = "image/bmp"; break;
  case "ico": $mime = "image/x-icon"; break;
  case "3gp": $mime = "video/3gpp"; break;
  case "3g2": $mime = "video/3gpp2"; break;
  case "mp4v": $mime = "video/mp4"; break;
  case "mpg4": $mime = "video/mp4"; break;
  case "m2v": $mime = "video/mpeg"; break;
  case "m1v": $mime = "video/mpeg"; break;
  case "mpe": $mime = "video/mpeg"; break;
  case "mpeg": $mime = "video/mpeg"; break;
  case "mpg": $mime = "video/mpeg"; break;
  case "mov": $mime = "video/quicktime"; break;
  case "qt": $mime = "video/quicktime"; break;
  case "avi": $mime = "video/x-msvideo"; break;
  case "midi": $mime = "audio/midi"; break;
  case "mid": $mime = "audio/mid"; break;
  case "amr": $mime = "audio/amr"; break;
  default: $mime = "application/force-download";
 }
header('Content-Description: File Transfer');
header('Content-Type: '.$mime);
header('Content-Disposition: attachment; filename='.basename($file));
header('Content-Transfer-Encoding: binary');
header('Expires: 0');
header('Cache-Control: must-revalidate, post-check=0, pre-check=0');
header('Pragma: public');
header('Content-Length: '. filesize($file));
ob_clean();
flush();

 readfile($file);
}   

if (isset($_POST['downl'])){
$file = "http://localhost/project1/downloads/gmf.mp4";
force_download($file); 

}
<form  method="POST" action=''>
    <?php echo'<input type="submit" name="downl"  value="Download Baby" >' ;    ?>
</form>

If i try to show file size with echo filesize($file) it gives this error :

 Warning: filesize(): stat failed for http://localhost/project1/downloads...

Upvotes: 0

Views: 615

Answers (1)

Ota
Ota

Reputation: 696

Since php 5.0.0 the file command supports http wrappers but the http wrapper does not support stat commands like size. So you cannot get the file size in your case with size.

Upvotes: 2

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