CODEWITHSUNDEEP
javaregexstring
Edison Miranda
Edison Miranda

Reputation: 333

Matching a pattern in String

Dont know how to ask more correctly, so will try as I can.

There is one example string where we are searching and another pattern String:

I need some way to figure out if example contains pattern (it comes to my mind something like example.indexOf(pattern) > - 1)

Pattern = "b*b"
Example = "gjsdng" - false;
Example = "bob" - true;
Example = "bab" - true;
Example = "gdfgbUbfg" - true;

Upvotes: 0

Views: 104

Answers (3)

Scheintod
Scheintod

Reputation: 8105

Brrrrr.

There is absolutely no need to create the Pattern multiple times. Just compile it once:

Pattern pattern = Pattern.compile( "b.b" );

Furthermore there is no need to match the whole String. Just to find one occurrence of the searched String. So this is what you're looking for:

assertFalse( pattern.matcher( "Gollum" ).find() );
assertTrue( pattern.matcher( "bob" ).find() );
assertTrue( pattern.matcher( "babe" ).find() );
assertTrue( pattern.matcher( "Alibaba" ).find() );

Upvotes: 0

Braj
Braj

Reputation: 46841

You can use String#matches(regex) method with .*?b.b.* regex pattern to match the text.

System.out.println("gjsdng".matches(".*?b.b.*"));    //false
System.out.println("bob".matches(".*?b.b.*"));       //true
System.out.println("bab".matches(".*?b.b.*"));       //true
System.out.println("gdfgbUbfg".matches(".*?b.b.*")); // true

Pattern explanation:

  .*?                      any character except \n (0 or more times
                           (matching the least amount possible))
  b                        'b'
  .                        any character except \n
  b                        'b'
  .*                       any character except \n (0 or more times
                           (matching the most amount possible))

Upvotes: 5

danyim
danyim

Reputation: 1293

.*b[A-Za-z]b.* is the regex pattern you are looking for.

  • b letter b in character 1 of pattern
  • [A-Za-z] any letter A-Z or a-z in character 2 of pattern

  • b letter b in character 3 of pattern

    System.out.println("bobby".matches(".*b[A-Za-z]b.*")); // true
System.out.println("gjsdng".matches(".*b[A-Za-z]b.*")); // false
System.out.println("bob".matches(".*b[A-Za-z]b.*")); // true
System.out.println("bab".matches(".*b[A-Za-z]b.*")); // true
System.out.println("gdfgbUbfg".matches(".*b[A-Za-z]b.*")); // true

http://docs.oracle.com/javase/7/docs/api/java/util/regex/Pattern.html

Upvotes: 0

Related Questions