CODEWITHSUNDEEP
bashshellunix
foobar
foobar

Reputation: 2943

Whats wrong with my shell script

I want to take a local file and zip it at some other temp location. Following is my code which is giving error

path="/home/tft/Downloads/ie.js"
temp="/home/tft/Downloads/Temp"
name=$(basename "$path")
echo "$path"
echo "$name"
echo "$temp"
echo "$temp/$name.zip" #Its output is also weird!
zip -r -j "$temp/$name.zip" $path

Getting below output:

 /bin/bash test.sh

/home/tft/Downloads/ie.js
ie.js
/home/tft/Downloads/Temp
.zipjstft/Downloads/Temp 
        zip warning: name not matched: /home/tft/Downloads/ie.js

)zip . -i /home/tft/Downloads/ie.js -r -j /home/tft/Downloads/Temp

Upvotes: 1

Views: 73

Answers (1)

konsolebox
konsolebox

Reputation: 75458

Your script is in DOS format. Convert it first to UNIX format:

sed -i 's|\r||' yourscript.sh

Or use dos2unix:

dos2unix yourscript.sh

The error messages you see is caused by having an extra character (carriage return \r) at the end of your values. This happens when your file's format is not UNIX but DOS since DOS' line endings is \r\n where UNIX only has \n.

Upvotes: 2

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